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Question

Write the value of sinA+sin3AcosA+cos3A

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Solution

We have,
sinA+sin3AcosA+cos3A=sin3A+sinAcos3A+cosA=2sin(3A+A2)cos(3AA2)2cos(3A+A2)cos(3AA2)=sin2A cosAcos2A cosA=sin2Acos2A=tan2A sinA+sin3AcosA+cos3A=tan2A


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