x = 2+\- 0.1

y = 2+\-0.2 find the x and y based on error

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Solution

your question is not understood are you asked for absolute error then

absolute error is
0.1 and 0.2

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^{If x = 2±0.1}

^{Y= 2±0.2 find the absolute error}

Find and correct the errors in the statement: 2x + 3y = 5xy

0.2 x + 0.1 y = 25

2 (x - 2) - 1.6 y = 116

\frac{16}{x + 3} + \frac{3}{y - 2} = 5; \frac{8}{x + 3} - \frac{1}{y - 2} = 0

{log}_{2} (x + y) = {log}_{3} (x - y) = \frac{log 25}{log 0.2}

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