Factorize: $x^{2} + 5 x - 104$

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Solution

First find the two numbers whose sum $= 5$ and product $= - 104$
Clearly, the numbers are $13$ and $8$ ,
[Since, $13 - 8 = + 5, 13 \times (- 8) = - 104$ ]
Now,
$x^{2} + 5 x - 104$
$= x^{2} + 13 x - 8 x - 104$
$= x (x + 13) - 8 (x + 13)$
$= (x + 13) (x - 8)$
$∴ x^{2} + 5 x - 104 = (x + 13) (x - 8)$

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Similar questions

x^{2} + 5 x - 104

Pickout and write the absolute term from the expression given below:

(1) x² + 5x = 8

(2) 5x³ − 4x² + 3x + 18

(3) 6x²y + 8y² + xy − 10

(4)

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x^{2} + 5 x + 6 = 0

x^{2} - 5 x + 6 = 0

x^{2} + 5 x - 6 = 0

x^{2} - 5 x - 6 = 0

x

| x^{2} - 5 x | > | x^{2} | - | 5 x |

x^{2} - 5 x + 6 = x^{2} + 5 x - 8

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