Question

$\frac{x}{2}-\frac{x}{3}=\frac{x}{4}+\frac{1}{2}$. Solve it.

Answer 1

Consider the given equation,

$$\begin{gathered} \frac{x}{2}-\frac{x}{3}=\frac{x}{4}+\frac{1}{2} \\ \Rightarrow \frac{x}{2}-\frac{x}{3}-\frac{x}{4}=\frac{1}{2} \\ \Rightarrow \frac{6x-4x-3x}{12}=\frac{1}{2} \\ \Rightarrow \frac{-x}{12}=\frac{1}{2} \\ \Rightarrow x=\frac{-12}{2} \\ \therefore x=-6 \end{gathered}$$

Thus, the solution is $x=-6$.