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Algebraic Expressions

(x-4)(x-5)(x-...

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(x-4)(x-5)(x-6)(x-7)=1680

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f (x) = (x - 4) (x - 5) (x - 6) (x - 7)

f (x) = (x - 4) (x - 5) (x - 6) (x - 7)

Q. One root of the

4 x^{3} - 5 x^{2} - 6 x + 7 = 0

x = 1

Q. Find the remainder when

x^{4} + 4 x^{3} - 5 x^{2} - 6 x + 7

x - 1

\int \frac{6 x + 7}{(x - 5) (x - 4)} d x

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