The correct option is D 4.35
Zn(30)=1s2 2s2 2p6 3s2 3p6 3d10 4s2
Zeff=Z−σ
4s is filled and we want to calculate Zeff for electon in 4s. Let 4s shell to be the n shell
So we have electrons corresponding to each shell are as:
n→1; (n−1)→18; (n−2) and below→10
<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}-->
σ=0.35×1+0.85×18+1×8+1×2=25.65
⇒Zeff=30−25.65=4.35