Question

Add : $3p^2{q}^2-4pq+5,-10p^2{q}^2,15+9pq+7p^2{q}^2$

Answer 1

Add the given terms:

Given,$3p^2{q}^2-4pq+5,-10p^2{q}^2,15+9pq+7p^2{q}^2$

On combining the like terms and adding them we get

$\begin{array}{rcl}& =& 3p^2{q}^2–4pq+5+(-10p^2{q}^2)+15+9pq+7p^2{q}^2\\ & =& 3p^2{q}^2–10p^2{q}^2+7p^2{q}^2–4pq+9pq+5+15\\ & =& p^2{q}^2(3-10+7)+pq(-4+9)+(5+15)\\ & =& p^2{q}^2\left(0\right)+pq\left(5\right)+20\\ & =& 5pq+20\end{array}$

Hence, on adding $3p^2{q}^2-4pq+5,-10p^2{q}^2,15+9pq+7p^2{q}^2$ we get $5pq+20$.