Cube of a number ending in $7$ will end in the digit_______

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Solution

Consider numbers which ends with $7$ .
$7^{3} = 7 \times 7 \times 7 = 343 17^{3} = 17 \times 17 \times 17 = 4913 27^{3} = 27 \times 27 \times 27 = 19683$
It can be observed that the cube of a number ending in $7$ will end in the digit $3$

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Similar questions

State true or false.

(i) Cube of any odd number is even.

(ii) A perfect cube does not end with two zeroes.

(iii) If square of a number ends with 5, then its cube ends with 25.

(iv) There is no perfect cube which ends with 8.

(v) The cube of a two digit number may be a three digit number.

(vi) The cube of a two digit number may have seven or more digits.

(vii) The cube of a single digit number may be a single digit number.

Question 48

Fill in the blanks to make the statements true.

Cube of a number ending in 7 will end in the digit ___

Cube of a number ending in 9 will always end with 9.

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