Find: 12 of 429
Evaluate the Expression:
The given expression is 12 of 429.
We know that “of” in an expression represents multiplication.
∴12 of 429=12×389
=199
=219
Hence, the required answer is 219.
{1(sec2θ−cos2θ)+1(cosec2θ−sin2θ)}(sin2θcos2θ)=1−sin2θcos2θ2+sin2θcos2θ
If f=x1+x2+13(x1+x2)3+15(x1+x2)5+... to ∞ and g=x−23x3+15x5+17x7−29x9+..., then f=d×g. Find 4d.