If a→=2i^-3j^+4k^, find its components in yz plane
Compute the required value
Given vector is a→=2i^-3j^+4k^
We know that, for a vector a→=axi^+ayj^+azk^, the components in yz plane is (ay2+az2)
Here,ax=2,ay=-3,az=4
Components in yz plane =(ay2+az2)
=-32+42=9+16=25=5units
Hence the components in yz plane is 5units
If a=2i^+3j^-k^,b=-i^+2j-4k^and c=i^+j^+k^,then what is the value of (a→×b→).(a→×c→)?