Integrate ∫e2xdx.
Solve the given integral
Given: ∫e2xdx
Now,
Put, u=2x
Then, 2dx=du
Now, replace these values in∫e2xdx and solve,
=∫eu.12du=12∫eudu=12eu+C=12e2x+C
Hence, Integral ∫e2xdx is12e2x+C.