Simplify :1216-23÷127-43
Given 1216-23÷127-43
1216-23÷127-43=163-23÷133-43=6-3-23÷3-3-43∵amn=amn=62÷34=6×63×3×3×3=49
Hence the simplified form of 1216-23÷127-43 is 49.
The sum of the series 23!+45!+67!+... to ∞ = ae. Find (a+3)2.
Find the value of x so that; (i) (34)2x+1=((34)3)3(ii) (25)3×(25)6=(25)3x(iii) (−15)20÷(−15)15=(−15)5x(iv) 116×(12)2=(12)3(x−2)