Solve: (x+2)(x+3)+(x−3)(x−2)−2x(x+1)=0
Given:
(x+2)(x+3)+(x−3)(x−2)−2x(x+1)=0
⇒x2+2x+3x+6+x2-3x-2x+6-2x2-2x=0⇒2x2-2x2+5x-2x+12=0⇒-2x=-12⇒x=6
Solve the following equation:
2xx−3+12x+3+3x+9(x−3)(2x+3)=0; x≠3,x≠−32