The degree of a monomial $x^{2} y^{2} z^{2}$ is

$6$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$2$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$3$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$8$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$6$

Here the degree of monomial of $x^{2} y^{2} z^{2}$ $=$ sum of exponents of all its variables
$= 2 + 2 + 2 = 6$
Hence the degree of given monomial is $6$ .
Therefore, option (A) is the correct option.

Suggest Corrections

Similar questions

x^{2} + y^{2} + z^{2} = r^{2}

x^{2} + y^{2} - z^{2} = r^{2}

x^{2} - y^{2} + z^{2} = r^{2}

z^{2} + y^{2} - x^{2} = r^{2}

x^{2} y^{2} + x^{2}

\frac{8 (x^{3} y^{2} z^{2} + x^{2} y^{3} z^{2} + x^{2} y^{2} z^{3})}{4 x^{2} y^{2} z^{2}}

8 (x^{3} y^{2} z^{2} + x^{2} y^{3} z^{2} + x^{2} y^{2} z^{3}) \div 2 x^{2} y^{2} z^{2}

If $x = r s i n α c o s β, y = r s i n α s i n β$ and $z = r c o s α$ , then

Join BYJU'S Learning Program