The factors of x4+y4+x2y2 is
(x2+y2)(x2+y2–xy)
(x2+y2)(x2–y2)
(x2+y2+xy)(x2+y2–xy)
Factorisation is not possible
The given algebraic expression is x4+y4+x2y2
∴x4+y4+x2y2=(x4+y4+2x2y2)–x2y2=(x2+y2)2–x2y2[byusingformulaa2+b2+2ab=a+b2]=(x2+y2)2–(xy)2
=(x2+y2+xy)(x2+y2–xy) Use formula a2–b2=(a-b)(a+b)
Hence, the factors of x4+y4+x2y2 is (x2+y2+xy)(x2+y2–xy)
Hence, the correct option is (C).
Divide x4−y4 by x2−y2.
Factorize
i) x4 - y4 + x2 - y2