Question

What is the value of $8-4x$ when $x=-3$?

Answer 1

Find the value of $8-4x$ when $x=-3$.

We know, $8-4x$

Now putting $x=-3$, we get

$\begin{array}{rcl}8-4x& =& 8-4\left(-3\right)\\ & =& 8+12\\ & =& 20\end{array}$

Hence, the required value of $8-4x$ is $20$ when $x=-3$