Question

Write cubes of first three multiples of $3$.

Answer 1

Find cubes of first three multiples of $3$:

First three multiples of $3$ are $3\times 1,3\times 2,3\times 3$ that is $3,6,9$.

Also,

$\begin{array}{rcl}{3}^3& =& 27\\ 6^3& =& 216\\ 9^3& =& 729\end{array}$

Hence, cubes of first three multiples of $3$ are $27,216,729$.