Oxidising and Reducing Nature
Trending Questions
What is the oxidation number of in ?
What is the oxidation number of in ?
Which among the following does not disproportionate in the alkaline medium?
What is the oxidation number of H in ?
Which of the following will have highest density?
CHCl3
CCl4
CH3Cl
CH2Cl2
- Stannane
- Silane
- Plumbane
- Germane
- Ge2+>Sn2+>Pb2+
- Sn2+>Ge2+>Pb2+
- Pb2+>Sn2+>Ge2+
- None of these
It is because of the inability of ns2 electrons of the valence shell to participate in bonding that
Sn2+ is oxidizing while Pb2+ is reducing
Sn2+ and Pb2+ are both oxidizing and reducing
Sn4+ is reducing while Pb4+is oxidizing
Sn2+ is reducing while Pb4+is oxidizing
Rationalise the given statements and give chemical reactions:
• Lead (II) chloride reacts with Cl2 to give PbCl4.
• Lead (IV) chloride is highly unstable towards heat.
• Lead is known not to form an iodide, PbI4.
2SO2 + O2 gives 2SO3 will be
Answer
Kc = 1.3*10-3/(0.0821*700)-1 = 7.4*10-2
I want to know in (0.0821*700)-1 means what especially power minus one means
- Strong reducing character of Pb4+
- Low electronegativity of Br– and I–
- Large size of Br– and I–
- Strong oxidising character of Pb4+
- Pb is more electropositive than Ge
- Ionic radii of Pb2+ and Pb4+are larger than those of Ge2+ and Ge4+
- Ionization potential of lead is less than that of Ge
- Lead is heavier than Germanium
- Ag>Cr>Mg>K
- Ag<Cr<Mg<K
- Ag>Cr>K>Mg
- Cr>Ag>Mg>K
- Sn4+
- Sn+
- Sn3+
- Sn
- C
- Sn
- Pb
- Si
- AlCl3
- PbCl2
- SnCl4
- SnCl2
Discuss the pattern of variation in the oxidation states of
B to Tl
C to Pb
What is the oxidation number of manganese in , , and ?
State one appropriate observation.
Excess Chlorine gas reacted with Ammonia gas.
Each of the following ions contains vanadium in a +5 oxidation state except:
(d) aluminium carbide into methane.
For elements A, B and C the standard reduction potential are +0.65V , -2.25V and -0.45V respectively. The correct order of their reducing power is:
A>C>B
B>C>A
C>B>A
A>B>C
- because I− get oxidised to I2
- because I− is a strong reducing agent
- because I2 is a gas
- because I− is a strong oxidising agent
The correct order of the oxidizing power of Cl2, Br2, I2 and O2 is:
Cl2>Br2>I2>O2
O2>I2>Cl2>Br2
Cl2>Br2>O2>I2
I2>O2>Br2>Cl2
- because Iodine has electronegativity value
- because I− is a strong reducing agent
- because I2 is a gas
- because Iodine has large size
Which is more stable ?
- Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
- Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
- Assertion is correct but Reason is incorrect
- Assertion is incorrect but Reason is correct