Equations of Motion
Trending Questions
Q. A block of mass m slides down on an inclined wedge of same mass m as shown in figure. Friction is absent everywhere. Acceleration of center of mass of the block and wedge is
- zero
- gsin2θ(1+sin2θ)
- gcos2θ(1+sin2θ)
- gsinθ(1+cosθ)
Q. A body of mass 10 kg is moving with a constant velocity 10 m/s. When a constant force acts for 4 s on it, it moves with a velocity 2 m/s in the opposite direction. The magnitude of force acting on the body is
- 30 N
- 10 N
- 45 N
- 50 N
Q. A body of mass 2 kg has an initial speed of 5 m/s. A force acts on it for some time in the direction of motion. The force-time graph is shown in the figure. The final speed of the body is
- 9.25 m/s
- 5 m/s
- 14.25 m/s
- 4.25 m/s
Q. An object of mass 10 kg moves at a constant speed of 10 ms−1. A constant force that acts for 4 s on the object gives it a speed of 2 ms−1 in the opposite direction. The magnitude of force acting on the object is (Take the direction of initial velocity as positive)
- 3 N
- 30 N
- 300 N
- 0.3 N
Q. An elevator and its load have a total mass of 800 kg. If the elevator, originally moving downward at 10 m/s, is brought to rest with constant deceleration in a distance of 25 m, the tension in the supporting cable will be (g=10 m/s2)
- 8000 N
- 11200 N
- 9600 N
- 6500 N
Q. A ship of mass 3×107 kg initially at rest is pulled by a force of 5×104 N through a distance of 3 m. Assume that the resistance due to water is negligible. The speed of the ship is
- 1.5 m/s
- 60 m/s
- 0.1 m/s
- 5 m/s
Q. A body under the action of a force
→F=6ˆi−8ˆj+10ˆk, acquires an acceleration of 1 m/s2. The mass of this body must be
→F=6ˆi−8ˆj+10ˆk, acquires an acceleration of 1 m/s2. The mass of this body must be
- 10 kg
- 20 kg
- 10√2 kg
- 2√10 kg