Maximum Height
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- 490 m
- 980 m
- 245 m
- 735 m
Two bodies are projected with the same velocity. If one is projected at an angle of 30∘ and the other at an angle of 60∘ to the horizontal, the ratio of the maximum heights reached is
3 :1
1 : 3
2 : 1
1 : 2
- 10 m
- 7.5 m
- 5 m
- 2.5 m
If the initial velocity of a projectile be doubled, keeping the angle of projection same, the maximum height reached by it will
Remain the same
Be doubled
Be quadrupled
Be halved
If time of flight of a projectile is 10 seconds. Range is 500 meters. The maximum height attained by it will be
125 m
50 m
100 m
150 m
- hmax=10 m, T=2.5 s
- hmax=15.625 m, T=1.77 s
- hmax=15.625 m, T=3.54 s
- hmax=3.54 m, T=0.125 s
Two bodies are thrown up at angles of 45∘ and 60∘, respectively, with the horizontal. If both bodies attain same vertical height, then the ratio of velocities with which these are thrown is
√23
2√3
√32
√32
Two guns A and B can fire bullets at speeds and respectively. From a point on a horizontal ground, they are fired in all possible directions. The ratio of maximum areas covered by the bullets fired by the two guns, on the ground is :
- g(t1+t2)24
- g(t1+t2)28
- g(t2−t1)24
- g(t2−t1)28
1 parsec = _________ metres.
- Be doubled
- Be quadrupled
- Remain the same
- Be halved
- Zero
- E2
- E√2
- E
- 10√34 m/s
- 20 m/s
- 40 m/s
- 10 m/s
- Negative slope and zero curvature
- Zero slope and negative curvature
- Zero slope and positive curvature
- Positive slope and zero curvature
Column IColumn IIi.Velocity at half of the maximum heighta.√2vii.Velocity at the maximum heightb.√3v/2iii. Change in velocity when its returns to the groundc.v√2iv. Average velocity when its reaches the maximum heightd.v2√52
- i – b ii – c iii – a iv – d
- i – a ii – c iii – d iv – b
- i – b ii – a iii – c iv – d
- i – a ii – c iii –b iv – d
Two masses M1 and M2 are attached to the ends of a string which passes over a pulley attached to the top of an inclined plane. The angle of inclination of the plane in θ.Take g=10 ms−2.
Two equal masses (m) are projected at the same angle (θ) from two points separated by their range with equal velocities (v). The total momentum at the point of their collision is
In a projectile motion, velocity at maximum height is
u cos θ2
ucos θ
u sin θ2
None of these
- 4h
- 6h
- h3
- 2h
- h+r28h
- 2h+r28h
- 2h−r28h
- h−r28h
(g=10 m/s2)
- 425
- 415
- 825
- 815
Take g=10 m/s2.
- 125 m
- 50 m
- 100 m
- 150 m
(Assume g=10m/s2)
Column -1Column -2(A)Net torque on the particle(P) 200 SI unitabout point of projection(B)Angular momentum of the(Q) 400 SI unitparticle about point ofprojection(C)Angular velocity of the(R)1.0 SI unitparticle about point ofprojection(S)None
- A−P, B−Q, C−R
- A−Q, B−Q, C−S
- A−Q, B−P, C−S
- A−P, B−Q, C−S
A ball is suspended by a thread of length l at the point O on the wall, forming a small angle β(β>α) with the vertical (see the figure). Then the thread with the ball was deviated through a small angle β and set free. Assuming the collision of the ball against the wall to be perfectly elastic, the period of oscillation of this pendulum is:
- T=2√lg[π2+sin−1(αβ)]
- T=2π√lg[π2+sin−1(αβ)]
- T=2π√lg[π2+cos−1(αβ)]
- T=2√lg[π2+cos−1(αβ)]
In a projectile motion, velocity at maximum height is
u cos θ2
ucos θ
u sin θ2
None of these
A shot is fired at an angle to the horizontal such that it strikes the hill while moving horizontally. Find initial angle of projection.
none of these
- 2Vsinθ2
- 2Vcosθ2
- 2Vsinθ
- None of these