Question

Question 75

Find the length of the largest pole that can be placed in a room of dimensions $12m\times 4m\times 3m$.

Answer 1

We have, $\Delta ACF$, in which $\angle C={90}^{\circ }$, CF = 3 m and AC $=\sqrt{(12{)}^2+(4{)}^2}m$
The length of the largest pole = Length of diagonal of cuboid (in shape of room)
$\Rightarrow (AF{)}^2=(AC{)}^2+(CF{)}^2\Rightarrow (AF{)}^2=(12{)}^2+(4{)}^2+(3{)}^2\Rightarrow AF=\sqrt{144+16+9}=\sqrt{169}=13m$