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Question

Question 75

Find the length of the largest pole that can be placed in a room of dimensions 12m×4m×3m.

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Solution

We have, ΔACF, in which C=90, CF = 3 m and AC =(12)2+(4)2 m
The length of the largest pole = Length of diagonal of cuboid (in shape of room)
(AF)2=(AC)2+(CF)2(AF)2=(12)2+(4)2+(3)2AF=144+16+9=169=13 m


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