Parallel Plate Capacitor Calculator is a free online tool that displays the capacitance value of the parallel plate capacitor. BYJU’S online parallel plate capacitor calculator tool performs the calculation faster and it displays the capacitance value in a fraction of seconds.
How to Use the Parallel Plate Capacitor Calculator?
The procedure to use the parallel plate capacitor calculator is as follows:
Step 1: Enter the area, separation distance, and x for the unknown value in the input field
Step 2: Now click the button “Calculate x” to get the capacitance value
Step 3: Finally, the capacitance of the parallel plate capacitor will be displayed in the output field
What is Meant by Parallel Plate Capacitors?
In Physics, the arrangement of electrodes and dielectric material forms a parallel plate capacitor. If the two parallel plates are connected across the battery, the plates are charged and the eclectic field is formed between the two plates. This kind of arrangement is called the parallel plate capacitor. But, it can be capable of storing only a finite amount of energy before the breakdown of the dielectric field occurs. The parallel plate capacitor consists of two plates with area “A”, which are separated by the distance “d”, then the capacitance of the parallel plate capacitors is given by the formula,
Parallel Plate Capacitor Formula, C = kε0 (A/d)
“A” = Area
“d” = Separation distance between two plates
“k” = Relative permittivity of the dielectric material
“ε0” = Permittivity of the space which is equal to 8.854 × 10−12 F/m
Solved Example on Parallel Plate Capacitor
Determine the capacitance of the parallel plate capacitor in air, whose area is 4.2 m2, and the separation distance between two plates is 0.5m.
Given that, the area, A is 4.2 m2
The separation distance between two plates “d” is 0.5 m.
We know that the relative permittivity “k” of dielectric material in the air is 1.
ε0 = 8.854 × 10−12 F/m
We know that the formula to calculate the capacitance of the parallel plate capacitor is
Now, substitute the values in the formula, we get
C =(1)(8.854 × 10−12) (4.2/0.5)
C = (1)(8.854 × 10−12 ) (8.4)
C = (8.4)(8.854 × 10−12 )
C = 74.373× 10−12
C = 7.437× 10−11 F
Hence, the capacitance of the parallel plate capacitor is 7.437× 10−11 F.