Atomic Mass Formula

Atomic mass is the total of the masses of the electrons, neutrons, and protons in an atom, or in a group of atoms, the average mass. When compared to protons or neutrons electrons have so much less mass that they don’t influence the calculation. Thus, the total of the masses of neutrons and protons is the atomic mass.

The relative atomic mass of an element is the average mass of the naturally-occurring isotopes of the element relative to the mass of an atom of 12C means one atom is given a relative atomic mass of exactly 12. Atomic mass usually is reported with no units or as atomic mass units. The formula for atomic mass is given below.

Atomic mass = Number of protons + Number of neutrons + Number of electrons

How to Calculate Atomic Mass?

There are three methods to know the atomic mass, depending on one’s circumstances.

1. Use the Periodic Table

If it’s one’s first encounter with chemistry, their tutor will want them to study how to make use of the periodic table to find the atomic weight of an element. This digit is typically written underneath an element’s representation. Search for a decimal number, which is the weighted average of the atomic masses of every natural isotope of an element.

Periodic Table of Elements

Periodic Table

2. Sum of Protons and Neutrons

Add up the mass of neutrons and protons to compute the atomic mass of a single atom of an element.

3. All Atoms of an Element – Weighted Average

The weighted average of every element’s isotopes grounded on their abundance in nature is the atomic weight of an element. It is simple to compute the atomic mass of an element with these tips. Usually, in these questions, one is provided with a list of isotopes with their natural abundance and their mass either as percent value or a decimal. Multiply each isotope’s abundance by its mass. If someone’s abundance is a percent, they should divide their solution by 100. Add these values up.

The solution is the whole atomic weight or atomic mass of the selected element. The atomic mass unit can be associated with other units of mass using the conversion factor.1u = 1.66054 X 10-24g

Atomic Mass of Elements

The atomic mass of some of the substance is tabulated below.

Substance Atomic mass
Calcium ion 40.1
Chloride Ion 35.5
Magnesium Ion 24.3
Potassium Ion 39.1

Relative Atomic Mass

The link between the mass of an element and the number of atoms it contains is the relative atomic mass of the element. By using this chemist work out the chemical formula. The relative atomic mass scale is used to compare the masses of different atoms.

First the hydrogen atom the lightest atom was originally assigned a relative atomic mass of 1 and the relative atomic mass of other atoms was compared with this.

Element Relative atomic mass
Carbon 12
Hydrogen 1
Oxygen 16
Magnesium 24
Nitrogen 14

Atomic Mass Problems

Some of the example problems based on atomic mass are given below.

Problem – 1:
Find the mass number of an element whose atomic number is 16 and the number of neutrons in its atom is 19.
Solution:
Atomic number or number of protons = 16
Number of Neutrons = 19
Mass number (A) = Number of neutrons + Number of protons
Mass number (A) = 19 + 16
Mass number (A) = 35
Problem – 2:
What is the atomic weight of an element that consists of two isotopes? Isotope A has an abundance of 75.00 percent, and its mass is 14.000 units. The Isotope B has a mass of 15.000 atomic mass units and an abundance of 25.00 percent.
Solution:
The word percentage abundance points out how many atoms of an isotope are made up of 100 atoms of the element.
In this instance, 100 atoms of the element would comprise 75 atoms of isotope A and 25 atoms of isotope B.
For computing the atomic weight of the element, we multiply the mass of individual isotopes by the decimal equivalent of their percentage abundance and then add the results.
Atomic mass = (14.000u x 0.7500) + (15.000u x 0.2500)
Atomic mass = 14.25u

Learn more about the atomic mass formula from the expert faculties at BYJU’S.

Practise This Question

A rectangular park is having a grass field of 18cm long and 15 cm wide such that there is a path of 1.5 cm along each of its sides extending outside on each side of the park. The area of the path is 108 ​cm2.​

Leave a Comment

Your email address will not be published. Required fields are marked *