# Cell Potential Formula

The driving force of the electron flow from anode to cathode shows a potential drop in the energy of the electrons moving into the wire.  The difference in potential energy between the anode and cathode is known as the cell potential in a voltaic cell.

The formula for cell potential is

$E_{cell}^{0}=E_{reduction}^{0}+E_{oxidation}^{0}$

## Solved Example

Example 1: A concentration cell was created by immersing two silver electrodes in 0.05M and 0.1M AgNO3 solution. Write cell representation, cell reactions and find the EMF of the concentration cell.

The cell representation:

$Ag^{1+}\left | Ag^{0} \right |\left | Ag^{1+} \right |Ag^{0}$

The cell reactions:

$A(-):Ag^{0}=Ag^{1+}+1e$

$C(+):Ag^{1+}+1e=Ag^{0}$

To find the EMF of a concentration element, you must use the following formula:

$E = \frac{RT}{F}X\ln(\frac{c_{1}}{c_{2}})$

c1>c2

Therefore,E = 0.08 V

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