**Projectile Motion Formula**

One often experiences many kinds of motions in our daily life.Â **Projectile motion**Â is one among them. A projectile is some body thrown in space or air. The Curved path with which the projectile travels is what is termed as trajectory. The free fall motion of any object in a horizontal path with constant velocity is** Projectile Motion**.

Projectile Motion FormulaÂ **(trajectory formula)Â **is articulated as

Where,

the velocity along the x-axis is V_{xÂ },

the initial velocity along the x-axis is V_{xo}Â ,

the velocity along the y-axis is V_{y}Â ,

the initial velocity along the y-axis is V_{yo}Â .

acceleration due to gravity is g, and

the time taken is t

Equations associated to the trajectory motion (projectile motion) are articulated as,

Where,

the initial Velocity is V_{o}Â ,

the component along the y-axis is sinÂ Î¸,

the component along the x-axis is cosÂ Î¸.

Projectile Motion formula is made use of to calculate the distance, velocity and time engaged in the projectile motion.

**Projectile Motion Solved Examples**

Underneath are questions based on projectile motion which may help one in their exam.

**ProblemÂ 1:Â **A body is projected with a velocity of 20 ms^{-1Â }at 50^{o}Â to the horizontal. Find

(i) Maximum height reached

(ii) Time of flight and

(iii) Range of the projectile.

**Answer:**

Initial Velocity V_{o}Â = 20 ms^{-1},

**= 3.126s**

Maximum height reached, H =

=11.97m

HorizontalÂ Â Range R =

=40.196m

**ProblemÂ 2:Â **John is on top of the building, and jack is down. If John tosses a ball at an angle of 60^{o}Â and with an initial velocity of 20 m/s, what height will the ball touch after 2 s?

**Answer:**

Given:

V_{yo}Â = 20 m/s,

Î”Â t = 2s,

The Vertical velocity in y-direction is articulated as V_{y}Â = V_{yo}Â sin 60^{o}