In mathematics subject, every function has an inverse. Similarly, the trigonometric function also comprises inverse. In trigonometry, arctan is the inverse of the tangent function and is used to compute the angle measure from the tangent ratio (tan = opposite/adjacent) of a right triangle. Arctan can be calculated in terms of degrees and as well as radians.
\(\begin{array}{l}\large \arctan (x)=2\arctan \left ( \frac{x}{1+\sqrt{1+x^{2}}} \right )\end{array} \)
\(\begin{array}{l}\large \arctan (x)=\int_{0}^{x}\frac{1}{z^{2}+1}dz\;;\;\left | x \right |\leq 1\end{array} \)
\(\begin{array}{l}\large \int \arctan (z)dz=z\arctan (z)-\frac{1}{2}\ln (1+z^{2})+C\end{array} \)
Arctangent formulas for \(\begin{array}{l}\pi\end{array} \)
\(\begin{array}{l}\large \frac{\pi }{4}=4\arctan \frac{1}{5}-\arctan \frac{1}{239}\end{array} \)
\(\begin{array}{l}\large \frac{\pi }{4}=\arctan\frac{1}{2}+\arctan \frac{1}{3}\end{array} \)
\(\begin{array}{l}\large \frac{\pi }{4}=2\arctan\frac{1}{2}-\arctan \frac{1}{7}\end{array} \)
\(\begin{array}{l}\large \frac{\pi }{4}=2\arctan\frac{1}{3}+\arctan \frac{1}{7}\end{array} \)
\(\begin{array}{l}\large \frac{\pi }{4}=8\arctan\frac{1}{10}-4\arctan \frac{1}{515}-\arctan \frac{1}{239}\end{array} \)
\(\begin{array}{l}\large \frac{\pi }{4}=3\arctan\frac{1}{4}+\arctan \frac{1}{20}+\arctan \frac{1}{1985}\end{array} \)
\(\begin{array}{l}\large \frac{\pi }{4}=24\arctan\frac{1}{8}+8\arctan \frac{1}{57}+4\arctan \frac{1}{239}\end{array} \)
Solved Example
Question : Evaluate: tan-1(1.732)
Solution:
The given value is, tan-1(1.732)
From this given quantity, 1.732 can be written as a function of tan.
So, 1.732 = tan 60°
Therefore, tan-1(1.732) = tan-1 (tan 60°) = 60°
60° = 60
\(\begin{array}{l}\times\end{array} \)
\(\begin{array}{l}\frac{\pi}{180}\end{array} \)
= 1.047 radians.
