Conditional probability formula gives the measure of the probability of an event given that another event has occurred. If the event of interest is A and the event B is known or assumed to have occurred, “the conditional probability of A given B”, or “the probability of A under the condition B”. The events are usually written as P(A|B), or sometimes P B(A). The formula for conditional probability for both the conditions i.e. “the probability of A under the condition B” and “the probability of B under the condition A” are stated below.

## Formula for Conditional Probability

Conditional Probability of A given B | P (A|B) = P(A ∩ B)⁄P(B) |

Conditional Probability of B given A | P (B|A) = P(B ∩ A)⁄P(A) |

### Solved Examples Using Conditional Probability Formula

**Question 1:**

The probability that it is Friday and that a student is absent is 0.03. Since there are 5 school days in a week, the probability that it is Friday is 0.2. What is the probability that a student is absent given that today is Friday?

**Solution:**

The formula of Conditional probability Formula is:

P (B|A) = P(A ∩ B)⁄P(A)

P(Absent | Friday)= P (Absent and Friday)⁄P(Friday)

= 0.03/0.2

= 0.15

= 15 %

**Question 2: A teacher gave her students of the class two tests namely maths and science. 25% of the students passed both the tests and 40% of the students passed the maths test. What percent of those who passed the maths test also passed the science test?**

Solution:

Given,

Percentage of students who passed the maths test = 40%

Percentage of students who passed both the tests = 25%

Let A and B be the events of the number of students who passed maths and science tests.

According to the given,

P(A) = 40% = 0.40

P(A ⋂ B) = 25% = 0.25

Percent of students who passed the maths test also passed the science test

= Condition probability of B given A

= P(B|A)

= P(A ⋂ B)/P(A)

= 0.25/0.40

= 0.625

= 62.5%

**Question 3: A bag contains green and yellow balls. Two balls are drawn without replacement. The probability of selecting a green ball and then a yellow ball is 0.28. The probability of selecting a green ball on the first draw is 0.5. Find the probability of selecting a yellow ball on the second draw, given that the first ball drawn was green.**

Solution:

Let A and B be the events of drawing a green in the first draw and yellow ball in the second draw respectively.

From the given,

P(A) = 0.5

P(A ⋂ B) = 0.28

Probability of selecting a yellow ball on the second draw, given that the first ball drawn was green = Conditional of B given A

= P(B|A)

= P(A ⋂ B)/P(A)

= 0.28/0.5

= 0.56

Amazing but still i would like to have more examples