Distance Speed Time Formula

 Speed Distance Time Formula

Speed is the rate at which an object moves. It’s a very basic concept in motion and all about how fast or slow an object can move. Speed is simply Distance divided by time where Distance is directly proportional to Velocity when time is constant. Problems related to Speed, Distance, and Time, will ask you to calculate for one of three variables given.

Formula for Speed Distance Time is mathematically given as:

Speed = Distance/Time


x = Speed in m/s,

d = Distance traveled in m,

t= time taken in s.

Distance traveled formula

Distance Formula

If any of the two values among speed, distance and time are given, we can use this formula and find the unknown quantity.


Question 1: Lilly is driving a scooty with the speed of 6 km/hr for 2hr. Calculate the distance traveled by her?



Speed of the scooty x = 6km/hr

Time taken t = 2 hr

Distance traveled d = ?

Speed distance time formula is given as


Distance traveled d = x × t

                            = 6 km/hr × 2 hr

                            = 12 km.

Question 2: A man has covered a distance of 80 miles in 4 hours. Calculate the speed of the bike?


Given : Distance Covered d = 80 miles,

Time taken t = 4 hours

Speed is calculated using the formula: x = d/t

                                                           = 80/4

                                                           = 20 miles/hr.

Question 3: In a cycle race, a cyclist is moving with the speed of 2 km/hr. He has to cover a distance of 5 km. Calculate the time will he need to reach his destiny?


Given: Speed x = 2 km/hr,

Distance Covered d = 5 km,

time taken t = ?

Speed is given by formula: x = d x t

Time taken t = x/d

                   = 2/5

                   = 0.4 hr

                   = 1440 s / 24 minutes

Time taken by the Cyclist = 0.4 hr

Practise This Question

Ted bought a new TV set. He decided to keep it on a shelf in the corner of the room at some height so that the view gets better. If AB = AC = 48 inches, is the space enough for a TV with an area of the base (as isosceles right triangle shape) equal to 1200 square inches so that no part of the TV lies outside the shelf? If not, what should be the minimum length of AB?