 # Perpendicular Line Formula

A perpendicular line is a straight line through a point. It makes an angle of 90 degrees with a particular point through which the line passes. Coordinates and line equation is the prerequisite to finding out the perpendicular line.

Consider the equation of the line is ax + by + c = 0 and coordinates are (x1, y1), the slope should be − a/b. If one line is perpendicular to this line, the product of slopes should be -1. Let m1 and m2 be the slopes of two lines, and if they are perpendicular to each other, then their product will be -1.

$\large Perpendicular\;Lines;\;m_{1}\times m_{2}=-1$

$\large Slope\;m=\frac{-a}{b}$

$\large Perpendicular\;Line \; equation:\; (y-y_{1})=m(x-x_{1})$

### Solved Example

Question: Check whether 2x + 3y + 5 = 0 and 3x – 2y + 1 = 0 are perpendicular or not.

Solution:

The given equations of lines are:
2x + 3y + 5 = 0 and 3x – 2y + 1 = 0

To check whether they are perpendicular to each other, find out the slopes of both lines. If the product of their slopes is -1, these lines are perpendicular to each other.

Slope formula is; m =

$$\begin{array}{l}\frac{-a}{b}\end{array}$$

Slope for first line,

$$\begin{array}{l}m_{1}\end{array}$$
=
$$\begin{array}{l}\frac{-a}{b}\end{array}$$
=
$$\begin{array}{l}\frac{-2}{3}\end{array}$$
/span>

Slope for second line,

$$\begin{array}{l}m_{2}\end{array}$$
$$\begin{array}{l}\frac{-a}{b}\end{array}$$
=
$$\begin{array}{l}\frac{-3}{-2}\end{array}$$

$$\begin{array}{l}m_{1}\times m_{2}\end{array}$$
=
$$\begin{array}{l}\frac{-2}{3}\end{array}$$
$$\begin{array}{l}\times\end{array}$$
$$\begin{array}{l}\frac{-3}{-2}\end{array}$$
= -1

Since the product of slope is -1, the given lines are perpendicular to each other.