# Force Of Attraction Formula

Force of attractionÂ is a force that pulls the body near due to its attraction.Â There are numerous attractive forces prevailing in nature.Â Some of them are magnetic force, electric force, electrostatic force and gravitational force.Â Gravitational force is very well-identified instanceÂ force of attraction as it draws objects towards itself regardless of its distance. Newton’s universal law of gravitation clarifies aÂ lot more about how this force performs. It states that every mass that occurs in the universe attracts some or the other mass in the universe. It validates the fact that anyone thrown up comes down.

Let’s take two masses m1Â and m2Â parted by a spaced.

The formula for the force of attraction is articulated as,

$$\begin{array}{l}F_{g} = \frac{G m_{1}m_{2}}{d^{2}}\end{array}$$

Where,

F is the force of attraction
G is the gravitational constant (6.67Â Ă—Â 10-11Â Nm2/kg2),
the mass of object 1 is m1,
the mass of object 2 is m2,
the distance between two objects is d.

This formula aids out in calculating the force acting amongst any two bodies having a greater mass since in smaller masses this force is insignificant.

### Solved Examples

Example 1:Â Compute the gravitational force acts amongst two bodies of masses 20,000 kg and 50,000 kg parted by a distance of 50 m.

Known:

mass m1Â = 20000 kg,

mass m2Â = 50000 kg,

radius r = 50 m,

Gravitational constant G = 6.67Â Ă—Â 10-11Â Nm2/kg2

The force due to gravity is articulated as,

$$\begin{array}{l}F_{g} = \frac{G m_{1}m_{2}}{r^{2}}\end{array}$$

$$\begin{array}{l}F=\frac{6.67 \times 10^{-11}Nm^{2}/Kg^{2} \times 20000 \times 50000}{50^{2}}\end{array}$$

$$\begin{array}{l}F=2.67 \times 10^{-5}N\end{array}$$

Therefore, the gravitational force isÂ

$$\begin{array}{l}2.67 \times 10^{-5}N\end{array}$$
between the two bodies.

Example 2:Â A body of weight 80 kg is 2 m far away from the body of weight 50 kg. Calculate the gravitational force acting between them.

Known:

mass m1Â = 80 kg,

mass m2Â = 50 kg,

radius r = 2 m,

Gravitational constant G = 6.67Â Ă—Â 10-11Â Nm2/kg2

$$\begin{array}{l}F_{g} = \frac{G m_{1}m_{2}}{r^{2}}\end{array}$$

$$\begin{array}{l}F = \frac{\left ( 6.67\times 10^{-11} \right )\times 80Kg \times 50Kg}{2^{2}}\end{array}$$

$$\begin{array}{l}F=6.67 \times 10^{-8}N\end{array}$$

Therefore,Â

$$\begin{array}{l}6.67 \times 10^{-8}N\end{array}$$
of gravitational force acts between the two bodies.

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