# Sandeep Garg Solutions for Class 11 Economics Chapter 8 - Measures of Correlation

Sandeep Garg Class 11 Economics Solutions Economics Chapter 8 – Measures of Correlation are illustrated by the professional economic educator from the contemporary edition of Sandeep Garg Economics Class 11 textbook solutions.

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## Sandeep Garg Solutions Class 11 – Chapter 8

Question1

Evaluate the coefficient of rank correlation of ten artisans of a facility that is ranked in terms of their capability by 2 separate judges:

 Artisans Name P Q R S T U V W X Y Position given Judge P 2 9 5 5 2 2 4 7 8 10 Position given Judge R 3 8 5 7 2 3 2 5 10 9

 Artisans Name Position given Judge RP Position given Judge RR D= RP−RR D2 P Q R S T U V W X Y 2 9 5 5 2 2 4 7 8 10 3 8 5 7 2 3 2 5 10 9 1 1 0 -2 0 -1 2 2 -2 1 1 1 0 4 0 1 4 4 4 1 ΣD2=20

N= 10

rk = 1 – 6ΣD2

Or, rk = $\frac{6X20}{1000-10}$

rk= 1 – 0.121

rk = 0.88

Hence, the coefficient of rank correlation is 0.88

Question 2

Evaluate the coefficient of rank correlation.

 Maths Marks 50 60 65 70 75 40 80 85 Accountancy Marks 80 71 60 75 90 82 70 50

 Maths Marks Accountancy Marks R1 R2 D= R1−R2 D2 50 60 65 70 75 40 80 85 80 71 60 75 90 82 70 50 2 3 4 5 6 1 7 8 6 4 2 5 8 7 3 1 −4 −1 2 0 −2 −6 4 7 16 1 4 0 4 36 16 49 ΣD2=126

N= 8

rk = 1 – 6ΣD2

Or, rk = $\frac{6X126}{512-8}$

rk = 0.5

Hence, the coefficient of rank correlation is 0.5

Question 3

What is the coefficient of rank correlation of the following information

 Subject A 3 5 8 4 7 10 2 1 6 9 Subject B 6 4 9 8 1 2 3 10 5 7

 RA RB D = RA− RB D2 3 5 8 4 7 10 2 1 6 9 6 4 9 8 1 2 3 10 5 7 −3 1 −1 −4 6 8 −1 −9 1 2 9 1 1 16 36 64 1 81 1 4 ΣD2=214

N= 10

rk = 1 – $\frac{6\sum D^{2}}{N^{3}-N}$

Or, rk = $\frac{6X214}{1000-10}$

rk = 0.2969

Hence, the coefficient of rank correlation is -0.297

Question 4

Evaluate rank correlation between advertisement sales and cost according to the following information

 Cost 78 36 98 25 75 82 90 62 65 39 Sales (in lakh ) 84 51 91 60 68 62 86 58 53 47

 Advertising Cost (X) Sales (Y) R1 R2 D= R1−R2 D2 78 36 98 25 75 82 90 62 65 39 84 51 91 60 68 62 86 58 53 47 7 2 10 1 6 8 9 4 5 3 8 2 10 5 7 6 9 4 3 1 −1 0 0 −4 −1 2 0 0 2 2 1 0 0 16 1 4 0 0 4 4 ΣD2=30

N= 10

rk = 1 – $\frac{6\sum D^{2}}{N^{3}-N}$

Or, rk = 1- $\frac{6X3}{1000-10}$

rk = 1 – 0.1818 = – 0.818

Hence, the coefficient of rank correlation is -0.82

Question 5

Evaluate rank coefficient of correlation.

 X 1 2 3 4 5 6 7 8 9 10 11 12 Y 12 9 6 10 3 5 4 7 8 2 11 1

 X Y R1 R2 D=R1−R2 D2 1 2 3 4 5 6 7 8 9 10 11 12 12 9 6 10 3 5 4 7 8 2 11 1 1 2 3 4 5 6 7 8 9 10 11 12 12 9 6 10 3 5 4 7 8 2 11 1 −11 −7 −3 −6 2 1 3 1 1 8 0 11 121 49 9 36 4 1 9 1 1 64 0 121 N = 12 ΣD2=416

Here, m= 0

rk = 1 – $\frac{6\sum D^{2}}{N^{3}-N}$

rk = 1- $\frac{6X416}{1728-12}$

Or, rk = 1 – $\frac{2946}{1716}$

rk = – 0.454

Hence, the coefficient of rank correlation is – 0.454

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