MSBSHSE Solutions For SSC (Class 10) Maths Part 1 Chapter 2- Quadratic Equations

MSBSHSE Solutions For SSC (Class 10) Maths Part 1 Chapter 2 Quadratic Equations are provided here to help students understand the concepts, right from the beginning. To score good marks in Class 10 Mathematics examination, it is advised they solve questions provided at the end of each chapter in the Maharashtra Board Textbooks for SSC Part 1. These Maharashtra Board Solutions for Class 10 Maths help the students in understanding all the concepts in a better way. Chapter 2 Quadratic Equations for Class 10 Maths explains the concepts related to quadratic equations and methods of solving them. Maharashtra State Board Solutions for Chapter 2, students will learn and solve problems based on topics like Quadratic polynomials, standard form, roots, solutions of a quadratic equation by factorisation and completing the square, nature of roots and relation between roots of the quadratic equation and coefficients.

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Practice set 2.1 Page no: 34

1. Write any two quadratic equations.

Solution:

Two quadratic equations are

a² + 16 = 0 and x² + 2x + 6 = 0

2. Decide which of the following are quadratic equations.

(1) x² + 5x – 2 = 0

Solution:

x² + 5x – 2 = 0 is a quadratic equation because it is the form of ax² + bx + c = 0 and it has degree 2.

(2) y² = 5y – 10

Solution:

y² = 5y – 10 is a quadratic equation because it is the form of ax² + bx + c = 0 and it has degree 2.

(3) y² + 1/y = 2

Solution:

y² + 1/y = 2 is a quadratic equation because it is the form of ax² + bx + c = 0 and it has degree 2.

(4) x + 1/x = -2

Solution:

Given equation can be written as

x² + 1 = -2x

x² + 2x + 1 = 0

It is a quadratic equation because it is the form of ax² + bx + c = 0 and it has degree 2.

(5) (m + 2) (m–5) = 0

Solution:

Given equation can be written as

m (m – 5) + 2 (m – 5)

= m² – 5m + 2m – 10

= m² – 3m + 10 = 0

It is a quadratic equation because it is the form of ax² + bx + c = 0 and it has degree 2.

(6) m³ + 3m² – 2 = 3 m³

Solution:

Given m³ + 3m² – 2 = 3 m³

It is not a quadratic equation because it is not in the form of ax² + bx + c = 0 and it has degree 3.

3. Write the following equations in the form ax² + bx + c = 0, then write the values of a, b, c for each equation.

(1) 2y = 10 – y²

Given

2y = 10 – y²

2y + y² – 10 = 0

y² + 2y – 10 = 0;

a = 1, b = 2, c = -10

(2) (x-1)² = 2x + 3

Solution:

(3) x² + 5x = – (3-x)

Solution:

(4) 3m² = 2m² – 9

Solution:

(5) P (3 + 6p) = – 5

Solution:

(6) x² – 9 = 13

Solution:

4. Determine whether the values given against each of the quadratic equation are the roots of the equation.

(1)  x² + 4x – 5 = 0, x = 1, -1

Solution:

(2) 2m² – 5m = 0, m = 2, 5/ 2

Solution:

∴ m = 2 is not root of the equation and m = 5/2 is a root of the equation.

5. Find k if x = 3 is a root of equation kx² – 10x + 3 = 0.

Solution:

6. One of the roots of equation 5m² + 2m + k = 0 is -7/5. Complete the following activity to find the value of ‘k’.

Solution:

Practice set 2.2 Page no: 36

1. Solve the following quadratic equations by factorization.

(1) x² – 15x + 54 = 0

Solution:

(2) x² + x – 20 = 0

Solution:

(3) 2y² + 27y + 13 = 0

Solution:

(4) 5m² = 22m + 15

Solution:

(5) 2x² – 2x + ½ = 0

Solution:

(2x – 1) (2x – 1)

2x – 1 = 0

x = ½, ½

Hence x = ½, ½ are the roots of the equation

(6) 6x -2/x = 1

Solution:

(7) √2 x² + 7 x + 5 √2 = 0 to solve this quadratic equation by factorization, complete the following activity.

(8) 3x² – 2 √6 x + 2 = 0

Solution:

(9) 2m (m-24) = 50

Solution:

(10) 25m² = 9

Solution:

(11) 7m² = 21m

Solution:

(12) m² – 11 = 0

Solution:

Practice set 2.3 Page no: 39

1. Solve the following quadratic equations by completing the square method.

(1) x² + x – 20 = 0

Solution:

(2) x² + 2x – 5 = 0

Solution:

(3) m² – 5m = -3

Solution:

(4) 9y² – 12y + 2 = 0

Solution:

Given

9y² – 12y + 2 = 0

The above equation can be written as

(3y)² – 2 × 3y × 4 + (4)² – (4)² + 2 = 0

(3y)² – 2 × 3y × 4 + (4)² – 16 + 2 = 0

(3y – 4)² – 14 = 0

(3y – 4)² = 14

3y – 14 = ±√143y = 14 ± √14y = (14 ± √14)/3

(5) 2y² + 9y + 10 = 0

Solution:

(6) 5x² – 4x + 7 = 0

Solution:

Practice set 2.4 Page no: 43

1. Compare the given quadratic equations to the general form and write values of a, b, c.

(1) x² – 7x + 5 = 0

Solution:

Given

x² – 7x + 5 = 0

comparing with ax² + bx + c

we get

a = 1, b = -7, c = 5

(2) 2m² = 5m – 5

Solution:

Given

2m² = 5m – 5

comparing with ax² + bx + c

we get

a = 2, b = -5, c = 5

(3)  y² = 7y

Solution:

Given

y² = 7y

comparing with ax² + bx + c

we get

a = 1, b = -7, c = 0

2. Solve using formula.

(1) x² + 6x + 5 = 0

Solution:

(2) x² – 3x – 2 = 0

Solution:

(3) 3m² + 2m – 7 = 0

Solution:

(4) 5m² – 4m – 2 = 0

Solution:

(5) y² + 1/3 y = 2

Solution:

(6) 5x² + 13x + 8 = 0

Solution:

3. With the help of the flow chart given below solve the equation  

using the formula.

Solution:

Practice set 2.5 Page no: 49

1. Fill in the gaps and complete.

Solution:

Roots are distinct and real when b² – 4ac = 5, not real when b² – 4ac = -5.

Solution:

x² + 7x + 5 = 0

Solution:

2. Find the value of discriminant.

(1) x² + 7x – 1 = 0

Solution:

(2) 2y² – 5y + 10 = 0

Solution:

(3) √2x² + 4x + 2 √2 = 0

Solution:

3. Determine the nature of roots of the following quadratic equations.

(1) x² – 4x + 4 = 0

Solution:

(2) 2y² – 7y + 2 = 0

Solution:

(3) m² + 2m + 9 = 0

Solution:

4. Form the quadratic equation from the roots given below.

(1) 0 and 4

Solution:

(2) 3 and -10

Solution:

(3) ½, – ½

Solution:

(4) 2 – √5, 2 + √5

Solution:

5. Sum of the roots of a quadratic equation is double their product. Find k if equation is x² – 4kx + k + 3 = 0

Solution:

6. a, b are roots of y2 – 2y – 7 = 0 find,

(1) α² + β²

Solution:

(2) α³ + β³

Solution:

7. The roots of each of the following quadratic equation are real and equal, find k.
(1) 3y² + ky + 12 = 0

Solution:

(2) kx (x-2) + 6 = 0

Solution:

Practice set 2.6 Page no: 52

1. Product of Pragati’s age 2 years ago and 3 years hence is 84. Find her present age.

Solution:

2. The sum of squares of two consecutive natural numbers is 244; find the numbers.

Solution:

3. In the orange garden of Mr. Madhusudan there are 150 orange trees. The number of trees in each row is 5 more than that in each column. Find the number of trees in each row and each column with the help of following flow chart.

Solution:

4. Vivek is older than Kishor by 5 years. The sum of the reciprocals of their ages is 1/6. Find their present ages.

Solution:

5. Suyash scored 10 marks more in second test than that in the first. 5 times the score of the second test is the same as square of the score in the first test. Find his score in the first test.

Solution:

Hence, score of first test is 10 as marks are not negative.

6. Mr. Kasam runs a small business of making earthen pots. He makes certain number of pots on daily basis. Production cost of each pot is ₹40 more than 10 times total number of pots, he makes in one day. If production cost of all pots per day is ` 600, find production cost of one pot and number of pots he makes per day.

Solution:

7. Pratik takes 8 hours to travel 36 km downstream and return to the same spot. The speed of boat in still water is 12 km. per hour. Find the speed of water current.

Solution:

8. Pintu takes 6 days more than those of Nishu to complete certain work. If they work together, they finish it in 4 days. How many days would it take to complete the work if they work alone.

Solution:

x = -4 is not possible, as no of days can’t be negative.

Nishu will take 6 days alone and Pintu takes 12 days alone

9. If 460 is divided by a natural number, quotient is 6 more than five times the divisor and remainder is 1. Find quotient and divisor.

Solution:

10. In the adjoining fig. □ABCD is a trapezium AB||CD and its area is 33 cm². From the information given in the figure find the lengths of all sides of the □ABCD. Fill in the empty boxes to get the solution.

Solution:

Problem set 2 Page no: 53

1. Choose the correct answers for the following questions.

(1) Which one is the quadratic equation?

Solution:

B. x (x + 5) = 2

Explanation:

It is in the form of ax² + bx + c

(2) Out of the following equations which one is not a quadratic equation?

A. x² + 4x = 11 + x²
B. x² = 4x
C. 5x² = 90
D. 2x – x² = x² + 5

Solution:

A. x² + 4x = 11 + x²

Explanation:

In all other options highest degree of equation is 2, which also the degree of quadratic equation. But in Option A, degree of polynomial is 1

(3) The roots of x² + kx + k = 0 are real and equal, find k.
A. 0
B. 4
C. 0 or 4
D. 2

Solution:

C. 0 or 4

Explanation:

4. For √2x² – 5x + √ 2 = 0 find the value of the discriminant.
A. -5
B. 17
C. 2

D. 2 √2 – 5

Solution:

B. 17

Explanation:

5. Which of the following quadratic equations has roots 3, 5?
A. x² – 15x + 8 = 0
B. x² – 8x + 15 = 0
C. x² + 3x + 5 = 0
D. x² + 8x – 15 = 0

Solution:

B. x² – 8x + 15 = 0

Explanation:

6. Out of the following equations, find the equation having the sum of its roots -5.
A. 3x² – 15x + 3 = 0
B. x² – 5x + 3 = 0
C. x² + 3x – 5 = 0
D. 3x² + 15x + 3 = 0

Solution:

A. 3x² – 15x + 3 = 0

Explanation:

7. √5 m² – √5m + √5 = 0 which of the following statement is true for this given equation?
A. Real and unequal roots
B. Real and equal roots
C. Roots are not real
D. Three roots.

Solution:

C. Roots are not real

Explanation:

8. One of the roots of equation x² + mx – 5 = 0 is 2; find m.
A. -2
B. – ½
C. ½
D. 2

Solution:

C. ½

Explanation:

2. Which of the following equations is quadratic?

(1) x² + 2x + 11 = 0
(2) x² – 2x + 5 = x²
(3) (x + 2)² = 2x²

Solution:

3. Find the value of discriminant for each of the following equation.

(1) 2y² – y + 2 = 0

Solution:

(2) 5m² – m = 0

Solution:

(3) √5x² – x – √5 = 0

Solution:

4. One of the roots of quadratic equation 2x² + kx – 2 = 0 is -2, find k.

Solution:

5. Two roots of quadratic equations are given; frame the equation.

(1) 10 and -10

Solution:

Let α = 10 and β = -10

∴ α + β = 10 – 10 = 0 α β = 10(-10)      = – 100

Quadratic equation is

x² – (α + β) x + α β = 0

⇒ x² – 0(x) – 100 = 0

⇒ x² – 100 = 0

(2) 1–3√5 and 1 + 3√5

Solution:

(3) 0 and 7

Solution:

6. Determine the nature of roots for each of the quadratic equation.

(1) 3x² – 5x + 7 = 0

Solution:

(2) √3x² + √2x – 2 √ 3 = 0

Solution:

(3) m² – 2m + 1 = 0

Solution:

7. Solve the following quadratic equation.

Solution:

Solution:

The roots are

(3) (2x + 3)² = 25

Solution:

(4) m² + 5m + 5 = 0

Solution:

(5) 5m² + 2m + 1 = 0

Solution:

(6) x² – 4x – 3 = 0

Solution:

8. Find m if (m – 12) x² + 2 (m – 12) x + 2 = 0 has real and equal roots.

Solution:

9. The sum of two roots of a quadratic equation is 5 and sum of their cubes is 35, find the equation.

Solution:

10. Find quadratic equation such that its roots are square of sum of the roots and square of difference of the roots of equation
2x² + 2 (p + q) x + p² + q² = 0

Solution:

11. Mukund possesses ₹50 more than what Sagar possesses. The product of the amount they have is 15,000. Find the amount each one has.

Solution:

12. The difference between squares of two numbers is 120. The square of smaller number is twice the greater number. Find the numbers.

Solution:

13. Ranjana wants to distribute 540 oranges among some students. If 30 students were more each would get 3 oranges less. Find the number of students.

Solution:

14. Mr. Dinesh owns an agricultural farm at village Talvel. The length of the farm is 10 meters more than twice the breadth. In order to harvest rain water, he dug a square shaped pond inside the farm. The side of pond is 1/3 of the breadth of the farm. The area of the farm is 20 times the area of the pond. Find the length and breadth of the farm and of the pond.

Solution:

15. A tank fills completely in 2 hours if both the taps are open. If only one of the taps is open at the given time, the smaller tap takes 3 hours more than the larger one to fill the tank. How much time does each tap take to fill the tank completely?

Solution:

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