Class 11 Maths Chapter 15 Statistics MCQs with solutions are provided at BYJU’S for students. The multiple-choice questions for Class 11 Maths Chapter 15 Statistics are prepared as per the latest exam pattern by our subject experts. The objective type questions are given here, as per the CBSE syllabus (2022 – 2023) and NCERT curriculum. By solving these MCQs on Statistics, students can have a revision for the chapter and also score better in the exam.
Also check: Class 11 Maths chapter-wise MCQs
MCQs for Class 11 Maths Chapter 15 Statistics
Class 11 Maths MCQs of Chapter 15 Statistics are provided here with the correct option. These multiple-choice questions are given here with proper explanations. The questions are based on the Statistics concept and related formulas. Students are advised to solve the MCQ questions on Statistics by themselves and then verify with the provided answers.
Download PDF – Chapter 15 Statistics MCQs
————————————————————————————————————————–
Q.1: Range of a data is equal to:
(a) Range = Max Value – Min Value
(b) Range = Max Value + Min Value
(c) Range = (Max Value – Min Value)/2
(d) Range = (Max Value + Min Value)/2
Answer: (a) Range = Max Value – Min Value
Q.2: Relation between mean, median and mode is given by:
(a) Mode = 2 Median – 3 Mean
(b) Mode = 2 Median + 3 Mean
(c) Mode = 3 Median – 2 Mean
(d) Mode = 3 Median + 2 Mean
Answer: (c) Mode = 3 Median – 2 Mean
Q.3: If the variance of the data is 121, the standard deviation of the data is:
(a) 121
(b) 11
(c) 12
(d) 21
Answer: (b) 11
Explanation:
Given, variance of the data = 121
Now, the standard deviation of the data = √(121)
= 11
Q.4: The geometric mean of series having mean = 25 and harmonic mean = 16 is:
(a) 16
(b) 20
(c) 25
(d) 30
Answer: (b) 20
Explanation:
The relationship between Arithmetic Mean (AM), Geometric Mean (GM) And Harmonic Mean (HM) is
GM² = AM × HM
Given AM = 25
HM = 16
So GM² = 25 × 16
⇒GM = √(25 × 16)
= 5 × 4
= 20
So, Geometric Mean = 20
Q.5: The coefficient of correlation r satisfies:
(a) I r I ≤ 1
(b) 0 < r < 1
(c) I r I > 1
(d) − 1 < r < 0
Answer: (a) I r I ≤ 1
Q.6: The coefficient of variation is computed by:
(i) S.D/.Mean×100
(ii) S.D./Mean
(iii) Mean./S.D×100
(iv) Mean/S.D.
Answer: (ii) S.D./Mean
Q.7: Find the median of 36, 72, 46, 42, 60, 45, 53, 46, 51, 49.
A. 42
B. 45.5
C. 47.5
D. 45
Answer: C. 47.5
Explanation: First we have to arrange the given observations into ascending order,
36, 42, 45, 46, 46, 49, 51, 53, 60, 72.
The number of observations is 10
Then,
Median = ((10/2)th observation + ((10/2)+ 1)th observation)/2
(10/2)th observation = 5th = 46
(10/2)+ 1)th observation = 5 + 1
= 6th = 49
Median = (46 + 49)/2
= 95
= 47.5
Q.8: Find the mean of 6, 7, 10, 12, 13, 4, 8, 12.
A. 9
B. 10
C. 12
D. 13
Answer: A. 9
Explanation: Mean = Sum of observations ÷ Number of observations
= (6 + 7 + 10 + 12 + 13 + 4 + 8 + 12)/8
= 72/8 = 9
Q.9: If the variance is 625, what is the standard deviation?
A. 5
B. 15
C. 25
D. None of the above
Answer: C. 25
Explanation: Given,
Variance, σ2 = 625
Standard deviation, σ = √625 = 25
Q.10: If the mean of first n natural numbers is 5n/9, n =
(a) 5
(b) 4
(c) 9
(d) 10
Answer: (c) 9
Explanation:
Given, mean of first n natural number is 5n/9
⇒ (n+1)/2 = 5n/9
⇒ n + 1 = (5n×2)/9
⇒ n + 1 = 10n/9
⇒ 9(n + 1) = 10n
⇒ 9n + 9 = 10n
⇒ 10n – 9n = 9
⇒ n = 9
Comments