Sequences and Series of Functions

As we already know how to define and write sequences and series of real numbers in mathematics. It is possible to define the sequence and series for functions, i.e., for real values functions. In this article, you will learn how to write the sequences and series of functions and the convergence of sequence and series of functions. Also, get the solved problems on sequences and series of functions here.

Learn in detail about sequences and series.

Sequences of Functions

Suppose fn be the real-valued function defined on E ⊆ R for each n ∈ N, then the set {fn}; n = 1, 2, 3, 4,…. is called the sequence of real-valued functions on E. It is denoted by {fn}, <fn> or {fn : E → R, n ∈ N.

Example:

If fn(x) = xn; x ∈ [0, 1] is a real valued function then the sequence of real valued functions is written as: {fn} = {f1(x), f2(x), f3(x),….} = {x, x2, x3,….} defined on [0, 1].

Series of Functions

Suppose {fn} be the sequence of real-values functions defined by E ⊆ R such that the expression

\(\begin{array}{l}\sum_{n=1}^{\infty}f_n\end{array} \)
is called the series of real-values functions.

Example:

Let fn(x) = (cos nx)/n2 defined on [0, 1] then the series of functions is given by:

\(\begin{array}{l}\sum_{n=1}^{\infty}f_n(x)=f_1(x) + f_2(x) + f_3(x)+….\end{array} \)

Read more:

Convergence of Sequences and Series of Functions

Now, you will learn about the convergence of series and sequence of functions. Let’s recall what is the convergence of a sequence and convergence of a series.

A sequence {an} is said to be convergent, if limn→∞ (an) = finite.

A series is convergent when it approaches a specific value as the series approaches infinity. It is denoted by

\(\begin{array}{l}\displaystyle \lim_{n \to \infty}\sum_{n=1}^{\infty}a_n=L\end{array} \)
.

Convergence of Sequence of Functions

When coming to the convergence of sequence and series of functions, we can define pointwise and uniform convergence.

Pointwise Convergence:

A sequence of functions fn: X → ℝ, where X is a subset of ℝ, converges pointwise on X to the function f: X → ℝ if and only if

limn→∞ fn(x) = f(x) ∀ x ∈ R

Here, fn(x) = f1(x), f2(x), f3(x),….

Uniform convergence

A sequence of functions fn(x); n = 1, 2, 3,…. Is said to be uniformly convergent to f for a set E of values of x, if for each ε > 0, a positive integer N exists such that |fn(x) – f(x)| < ε for n ≥ N and x ∈ E.

Alternatively, we can define the uniform convergence of a sequence of functions, as follows.

A sequence of functions fn(x); n = 1, 2, 3,…. Is said to be converges uniformly to f if and only if;

\(\begin{array}{l}\displaystyle \lim_{n \to \infty}\left ( \displaystyle \sup_{x\epsilon E}|f_n(x)-f(x)| \right )=0\end{array} \)

That means, supx∈E |fn(x) – f(x)| → 0 as n → ∞.

Convergence of Series of Functions

Pointwise convergence:

A series of functions

\(\begin{array}{l}\sum_{k=1}^{\infty}f_k(x)\end{array} \)
converges pointwise to S(x) on X if and only if

\(\begin{array}{l}\displaystyle \lim_{n \to \infty}\left [ \sum_{k=1}^{n}f_k(x) \right ]=S(x); \forall x\epsilon X\end{array} \)

Uniform convergence:

A series of functions ∑fn(x); n = 1, 2, 3,… is said to be uniformly convergent on E if the sequence {Sn} of partial sums defined by

\(\begin{array}{l}\sum_{k=1}^{n}f_k(x) =S_n(x)\end{array} \)
.

Alternatively, we can define the uniform convergence of a series as follows.

Suppose gn(x) : E → ℝ is a sequence of functions, we can say that the series

\(\begin{array}{l}\displaystyle \sum_{k=1}^{\infty}g_k(x)\end{array} \)
converges uniformly to S(x) on E if and only if the partial sum
\(\begin{array}{l}S_n(x)=\displaystyle \sum_{k=1}^{n}g_k(x)\end{array} \)
converges uniformly to S(x) on E.

Solved Example

State and prove Cauchy’s criterion for uniform convergence of sequence of functions.

Statement:

A sequence of functions {fn} is defined on E converges uniformly on E if and only if given ε > 0 there exists m ∈ N such that |fn+p (x) – fn(x)| < ε for all n ≥ m, p ≥ 1 and x ∈ E.

Proof:

Let us assume that the sequence of function {fn} defined on E converges uniformly to limit function f.

Therefore, for ε > 0 there exists m ∈ N such that

|fn(x) – f(x)| < ε/2 for all n ≥ m and x ∈ E……(1)

From the given statement, n ≥ m, p ≥ 1 and x ∈ E

So, |fn+p (x) – f(x)| < ε/2……(2)

Now,

|fn+p (x) – fn(x)| = |fn+p(x) – f(x) + f(x) – fn(x)|

≤ |fn+p(x) – f(x)| + |f(x) – fn(x)|

≤ |fn+p(x) – f(x)| + |fn(x) – f(x)|

< (ε/2) + (ε/2) [from (1) and (2)]

< ε

Thus, |fn+p (x) – fn(x)| < ε for all n ≥ m, p ≥ 1 and x ∈ E.

Hence proved.

Problems on Sequences and Series of Functions

  1. Show that the sequence of functions {fn} where fn(x) = xn/n defined on [0, 1] converges uniformly to 0.
  2. Show that the sequence of functions, {fn}, where fn(x) = tan-1(nx), x ≥ 0 converges uniformly on [a, b], a > 0 but is only pointwise convergent on [0, b].
  3. Show that x = 0 is a point of non-uniform convergence of the series x2 + [x2/(1 + x2)] + [x2/(1 + x2)2] + ……

To learn more about the functions of sequences and series, download BYJU’S – The Learning App today!

Comments

Leave a Comment

Your Mobile number and Email id will not be published.

*

*