Samacheer Kalvi 8th Maths Book Solutions Term 3 Chapter 4 – Statistics is available here. The Samacheer Kalvi 8th Maths book answers of Term 3 Chapter 4, available at BYJU’S, contain step by step explanations designed by our mathematics experts. All these important questions are based on the new pattern prescribed by the Tamil Nadu board. Students can also get the solutions of other chapters on samacheer kalvi 8th maths solutions.
Term 3 Chapter 4 of the Samacheer Kalvi 8th Maths guide will help the students to solve problems related to data, types of data, frequency distribution, graphical representation of grouped and ungrouped data.
Samacheer Kalvi 8th Maths Term 3 Chapter 4: Statistics Book Exercise 4.1 Questions and Solutions
Question 1: Represent the following data in an ungrouped frequency table which gives the number of children in 25 families. 1, 3, 0, 2, 5, 2, 3, 4, 1, 0, 5, 4, 3, 1, 3, 2, 5, 2, 1, 1, 2, 6, 2, 1, 4.
Solution:
The given data is raw in nature.
Ascending order 0, 1, 2, 3, 4, 5, 6.
Number of children 
Tally marks 
Frequency 
0 
 
2 
1 

6 
2 

6 
3 
 
4 
4 
 
3 
5 
 
3 
6 
 
1 
Total 
25 
Question 2: Draw a pie chart for the following information.
Solution:
Ocean 
Water (in %) 
Central angle 
Pacific 
46 
(46 / 100) * (360^{o}) = 165.6^{o} 
Atlantic 
24 
(24 / 100) * (360^{o}) = 86.4^{o} 
Indian 
20 
(20 / 100) * (360^{o}) = 72^{o} 
Arctic 
4 
(4 / 100) * (360^{o}) = 14.4^{o} 
Antarctic 
6 
(6 / 100) * (360^{o}) = 21.6^{o} 
Total 
100 
360^{o} 
Question 3: Write any five points from the given pie chart information regarding pollutants entering the oceans.
Solution:
1] The pie chart gives information about the number of pollutants entering the ocean from various sources.
2] 30% of the ocean is polluted by sewage.
3] 20% of the ocean is polluted by air.
4] Farm runoff equally contributes as much as air in polluting ocean.
5] The observation is about offshore oil, litter, industrial wastewater, maritime transportation, air pollutants, farm runoff and sewage.
Samacheer Kalvi 8th Maths Term 3 Chapter 4: Statistics Book Exercise 4.2 Questions and Solutions
Question 1: In a village, there are 570 people who have cell phones. An NGO surveys their cell phone usage. Based on this survey a histogram is drawn. Answer the following questions.
(i) How many people use the cell phone for less than 3 hours?
(ii) How many of them use the cell phone for more than 5 hours?
(iii) Are people using the cell phone for less than 1 hour?
Solution:
(i) 110 + 220 = 330 people use the cell phone for less than 3 hours.
(ii) 100 + 50 = 150 of them use the cell phone for more than 5 hours.
(iii) No
Question 2: Draw a histogram for the following data.
Solution:
Question 3: In a study of dental problem, the following data were obtained.
Represent the above data by a frequency polygon.
Solution:
On finding the midpoints of the class interval,
Ages 
Midpoint (x) 
Number of patients 
0 – 10 
5 
5 
10 – 20 
15 
13 
20 – 30 
25 
25 
30 – 40 
35 
14 
40 – 50 
45 
30 
50 – 60 
55 
35 
60 – 70 
65 
43 
70 – 80 
75 
50 
A frequency polygon is plotted by taking midpoints and number of patients.
Samacheer Kalvi 8th Maths Term 3 Chapter 4: Statistics Book Exercise 4.3 Questions and Solutions
Question 1: Draw a pie chart for the given table.
Solution:
Continent 
Area (in %) 
Central angle 
Asia 
30 
(30 / 100) * (360^{o}) = 108^{o} 
Africa 
20 
(20 / 100) * (360^{o}) = 72^{o} 
North America 
16 
(16 / 100) * (360^{o}) = 57.6^{o} 
South America 
12 
(12 / 100) * (360^{o}) = 43.2^{o} 
Europe 
7 
(7 / 100) * (360^{o}) = 25.2^{o} 
Australia 
6 
(6 / 100) * (360^{o}) = 21.6^{o} 
Antarctica 
9 
(9 / 100) * (360^{o}) = 32.4^{o} 
Total 
100 
360^{o} 
Question 2: Draw a histogram for the given frequency distribution.
Solution:
The given distribution is discontinuous.
Lower boundary = Lower limit – (1 / 2) (gap between the adjacent class interval)
= 41 – (1 / 2) * (1) = 40.5
Upper boundary = Upper limit + (1 / 2) (gap between the adjacent class interval)
= 45 + (1 / 2) (1) = 45.5
The continuous frequency table is as follows:
Age 
40.5 – 45.5 
45.5 – 50.5 
50.5 – 55.5 
55.5 – 60.5 
60.5 – 65.5 
65.5 – 70.5 
70.5 – 75.5 
Frequency 
4 
9 
17 
25 
15 
8 
2 