Class 11 Maths Chapter 16 Probability MCQs are available for students here with solutions and explanations. Multiple-choice questions for Class 11 Probability are prepared as per the latest exam pattern and CBSE syllabus. Students can practise the Class 11 Maths MCQs here at BYJU’S to score good marks in the exams. The objective-type questions here are prepared by our subject teachers following the guidelines under the NCERT curriculum.
MCQ Questions for Class 11 Maths Chapter 16 Probability
Class 11 Maths MCQs of Chapter 16 Probability is provided here with the correct options. These multiple-choice questions for probability are given here with proper explanations to help Class 11 students understand better. The MCQ questions are based on the Probability concept and related formulas. Solve the questions on your own and verify your answers with the given correct answers for each MCQ.
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Q.1: What is the total number of sample spaces when a die is thrown 2 times?
A. 6
B. 12
C. 18
D. 36
Answer: D. 36
Explanation: The possible outcomes when a die is thrown are 1, 2, 3, 4, 5, and 6.
Given, a die is thrown two times.
Then, the total number of sample spaces = (6 × 6)
= 36
Q.2: What is the total number of sample spaces when a coin is tossed and a die is thrown?
A. 6
B. 12
C. 8
D. 16
Answer: B. 12
Explanation: The possible outcomes when a coin is tossed are Head (H) or Tail (T).
The possible outcomes when a die is thrown are 1, 2, 3, 4, 5, and 6.
Then, total number of space = (2 × 6) = 12
Q.3: Three identical dice are rolled. What is the probability that the same number will appear on each of them?
A. 1/6
B. 1/36
C. 1/18
D. 3/28
Answer: B. 1/36
Explanation:
Total number of cases = 6³ = 216
The same number can appear on each of the dice in the following ways:
(1, 1, 1), (2, 2, 2), ………….(3, 3, 3)
So, favourable number of cases = 6
Hence, required probability = 6/216 = 1/36
Q.4: A bag contains 5 brown and 4 white socks. Ram pulls out two socks. What is the probability that both the socks are of the same colour?
A. 9/20
B. 2/9
C. 3/20
D. 4/9
Answer: D. 4/9
Explanation:
Total number of socks = 5 + 4 = 9
Two socks are pulled.
Now, P(Both are same colour) = (5C2 + 4C2)/9C2
= {(5×4)/(2×1) + (4×3)/(2×1)}/{(9×8)/(2×1)}
= {(5×4) + (4×3)/}/{(9×8)
= (5 + 3)/(9×2)
= 8/18
= 4/9
Q.5: What is the probability of getting the number 6 at least once in a regular die if it can roll it 6 times?
A. 1 – (5/6)6
B. 1 – (1/6)6
C. (5/6)6
D. (1/6)6
Answer: A. 1 – (5/6)6
Explanation:
Let A be the event that 6 does not occur at all.
Now, the probability of at least one 6 occurs = 1 – PA.
= 1 – (5/6)6
Q.6: Events A and B are said to be mutually exclusive if:
A. P (A U B) = P A. + P B.
B. P (A ∩ B) = P A. × P B.
C. P(A U B) = 0
D. None of these
Answer: A. P (A U B) = P A. + P B.
Explanation:
If A and B are mutually exclusive events,
Then P(A ∩ B) = 0
Now, by the addition theorem,
P(A U B) = PA. + PB. – P(A ∩ B)
⇒ P(A U B) = PA. + PB.
Q.7: A die is rolled. What is the probability that an even number is obtained?
A. 1/2
B. 2/3
C. 1/4
D. ¾
Answer: A. 1/2
Explanation:
When a die is rolled, total number of outcomes = 6 (1, 2, 3, 4, 5, 6)
Total even number = 3 (2, 4, 6)
So, the probability that an even number is obtained = 3/6 = ½
Q.8: What is the probability of selecting a vowel in the word “PROBABILITY”?
A. 2/11
B. 3/11
C. 4/11
D. 5/11
Answer: B. 3/11
Q.9: An urn contains 6 balls of which two are red and four are black. Two balls are drawn at random. What is the probability that they are of different colours?
A.⅖
B.1/15
C.8/15
D.4/15
Answer: C. 8/15
Explanation:
Given that, the total number of balls = 6 balls
Let A and B be the red and black balls, respectively,
The probability that two balls are drawn are different = P (the first ball drawn is red)(the second ball drawn is black)+ P (the first ball drawn is black)P(the second ball drawn is red)
= (2/6)(4/5) + (4/6)(2/5)
=(8/30)+ (8/30)
= 16/30
= 8/15
Q.10: 20 cards are numbered from 1 to 20. If one card is drawn at random, what is the probability that the number on the card is a prime number?
A. ⅕
B. ⅖
C. ⅗
D. 5
Answer: B. ⅖
Explanation:
Let E be the event of getting a prime number.
E = {2, 3, 5, 7, 11, 13, 17, 19}
Hence, P(E) = 8/20 = 2/5.
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