**Parabola:**

Parabola is locus of all points which are equally spaced from a fixed line and a fixed point.

- The fixed point is called, focus of the parabola.
- Fixed line is called, directrix of the parabola.

In the above figure, F is the focus and line with points A, B and C is the directrix.

According to definition of parabola,

AM = MF

BN = NF

CO = OF

**Axis of parabola** is a line which is perpendicular to the directrix and passes through the focus of parabola.

**Vertex of a parabola** is the point of intersection of axis and the parabola. Point O is the vertex of the parabola, as shown in the figure below.

**Standard equation of a parabola**

Consider parabola in the given figure,

The simplest form of equation of parabola is found when the vertex is at origin in the coordinate plane.

Let point F(a,0) be focus and O(0,0) be vertex of the parabola. A and B are two points on directrix and point P(x,y) is any point on parabola.

By definition of parabola, O is the mid point of AF and O is vertex of the parabola.

That is, AO = OF and coordinates of A will be (-a,0).

Therefore, equation of the directrixis x+a=0.

Also, FP = AB, (by the definition of parabola)

Since,PB is perpendicular to directrix, coordinates of B is (-a,y)

Using distance formula we get,

\( \sqrt{(x- a)^2 ~+ ~y^2} ~=~ \sqrt{(x~ + ~a)^2} \)

\( (x~-~a)^2~ +~ y^2 ~=~ (x~+~a)^2 \)

\( x^2~ -~2ax ~+~ a^2~ +~ y^2~ =~x^2~+~2ax~+~a^2\)

\(y^2~=~4ax\) —(1)

This is equation for a parabola whose focus is at (a,0)where a > 0.

Important points to note:,

- Equation of the parabola for figure given below is,

\(y^2\)=-4ax —(2)

- Equation of the parabola for figure given below is,

\(x^2\)=4ay —(3)

- Equation of the parabola for figure given below is,

\(x^2\)=-4ay —(4)

The equations (1), (2), (3) and (4) are known as standard equations of parabola.

**Length of Latus rectum**

Latus rectum of a parabola is the line segment perpendicular to axis through focus and its end points lie on the parabola.

Length of latus rectum of the parabola \(y^2~=~4ax\) is given by,

AB is the latus rectum of the above parabola with focus F(a,0).

ABis perpendicular to the X- axis.

Perpendicular distance between the directrix and the focus is,

NF = 2a =AM

By definition of parabola,

AM = AF = 2a

Similarly,

FB = 2a

Therefore,

*length of latus rectum* = 2a + 2a = 4a

4a = 16,a = 4 Co-ordinate of Focus of the parabola is (4,0)
We know, the Equation of directrix is x + a = 0 \(\Rightarrow\) x = – a Thus x = -4
Length of latus rectum is, 4a = 4 × 4 = 16 units |

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