Important questions for Class 8 Maths Chapter 14 factorization provided here with solutions. The questions are prepared as per Class 8 Maths CBSE syllabus (2022-2023) and the latest exam pattern. These questions cover various short answer type questions, long answer type questions and HOTS (High Order Thinking Skills) questions. These factorization extra questions will help CBSE students to be well-prepared for the Class 8 exam. Here, some important questions related to factorization topic from the NCERT Class 8 book are also included.
Also Check:
- Important 2 Marks Questions for CBSE 8th Maths
- Important 3 Marks Questions for CBSE 8th Maths
- Important 4 Marks Questions for CBSE 8th Maths
Factorization Important Questions For Class 8 (Chapter 14)
Some extremely important Class 8 questions from Chapter 14 i.e. factorization are provided below. Go through these factorization problems for better practice.
Short Answer Type Questions:
1. Express the following as in the form of (a+b)(a-b)
(i) a2 – 64
(ii) 20a2 – 45b2
(iii) 32x2y2 – 8
(iv) x2 – 2xy + y2 – z2
(v) 49x2 – 1
Solution:
For representing the expressions in (a+b)(a-b) form, use the following formula
a2 – b2 = (a+b)(a-b)
(i) a2 – 64 = a2 – 82 = (a + 8)(a – 8)
(ii) 20a2 – 45b2 = 5(4a2 – 9b2) = 5(2a + 3b)(2a – 3b)
(iii) 32x2y2 – 8 = 8( 4x2y2 – 1) = 8(2xy + 1)(2xy – 1)
(iv) x2 – 2xy + y2 – z2 = (x – y)2 – z2 = (x – y – z)(x – y + z)
(v) 49x2 – 1 = (7x)2 – (1)2 = (7x + 1)(7x – 1)
2. Verify whether the following equations are correct. Rewrite the incorrect equations correctly.
(i) (a + 6)2 = a2 + 12a + 36
(ii) (2a)2 + 5a = 4a + 5a
Solution:
(i) (a + 6)2 = a2 + 12a + 36
Here, LHS = (a + 6)2 = a2 + 12a + 36
Now, RHS = a2 + 12a + 36
Hence, LHS = RHS.
(ii) (2a)2 + 5a = 4a + 5a
Here, LHS = (2a)2 + 5a = 4a2 + 5a
Now, RHS = 4a + 5a
So, LHS ≠RHS
Correct equation: (2a)2 + 5a = 4a2 + 5a
3. For a = 3, simplify a2 + 5a + 4 and a2 – 5a
Solution:
Substitute the value of a = 3 in the given equations.
a2 + 5a + 4 = 32 + 5(3) + 4 = 9 + 15 + 4 = 28
And,
a2 – 5a = 32 – 5(3) = 9 – 15 = -6
Long Answer Type Questions:
4. Find the common factors of the following:
(i) 6 xyz, 24 xy2 and 12 x2y
(ii) 3x2 y3, 10x3 y2 and 6x2 y2 z
Solution:
(i) 6 xyz = 2 × 3 × x × y × z
24 xy2 = 2 × 2 × 2 × 3 × x × y × y
12 x2y = 2 × 2 × 3 × x × x × y
Thus, the common factors are common factors of 6 xyz, 24 xy2 and 12 x2y are 2, 3, x, y and, (2 × 3 × x × y) = 6xy
(ii) 3x2 y3 = 3 × x × x × y × y × y
10x3 y2 = 2 × 5 × x × x × x × y × y
6 x2 y2 z = 3 × 2 × x × x × y × y × z
Now, the common factors of 3x2 y3, 10x3 y2 and 6x2 y2 z are x2, y2 and, (x2 × y2) = x2 y2
5. Factorize the following expressions:
(i) 54x3y + 81x4y2
(ii) 14(3x – 5y)3 + 7(3x – 5y)2
(iii) 15xy + 15 + 9y + 25x
Solution:
(i) 54x3y + 81x4y2
= 2 × 3 × 3 × 3 × x × x × x × y + 3 × 3 × 3 × 3 × x × x × x × x × y × y
= 3 × 3 × 3 × x × x × x × y × (2 + 3 xy)
= 27x3y (2 + 3 xy)
(ii) 14(3x – 5y)3 + 7(3x – 5y)2
= 7(3x – 5y)2 [2(3x – 5y) +1]
= 7(3x – 5y)2 (6x – 10y + 1)
(iii) 15xy + 15 + 9y + 25x
Rearrange the terms as:
15xy + 25x + 9y + 15
= 5x(3y + 5) + 3(3y + 5)
Or, (5x + 3)(3y + 5)
6. Factorize (x + y)2 – 4xy
Solution:
To solve this expression, expand (x + y)2
Use the formula:
(x + y)2 = x2 + 2xy + y2
(x + y)2 – 4xy = x2 + 2xy + y2 – 4xy
= x2 + y2 – 2xy
We know, (x – y)2 = x2 + y2 – 2xy
So, factorization of (x + y)2 – 4xy = (x – y)2
7. Factorize x2 + 6x – 16
Solution:
To factorize, it should be checked that the sum of factors of 16 should be equal to 6.
Here, 16 = -2 × 8 and 8 + (-2) = 6
So,
x2 + 6x – 16 = x2 – 2x + 8x – 16
= x(x – 2) + 8(x – 2)
= (x + 8) (x – 2)
Hence, x2 + 6x – 16 = (x + 8) (x – 2)
8. Solve for (4x2 – 100) ÷ 6(x + 5)
Solution:
= â…” (x – 5)
Class 8 Maths Chapter 14 Extra Questions
- Factorise:
(а) 14m5n4p2 – 42m7n3p7 – 70m6n4p3
(b) 2a2(b2 – c2) + b2(2c2 – 2a2) + 2c2(a2 – b2) -  The area of a rectangle is 6a2 + 36a and 36a width. Find the length of the rectangle.
- What are the common factors of the following terms?
(a) 25x2y, 30xy2
(b) 63m3n, 54mn4
Topics Related to Class 8 Factorization
Download BYJU’S-The Learning App and get interactive videos based on Class 8 Maths concepts.
Questions are very good
I really liked them
It is very helpful for the revision of periodic tests and exams
Really Helpfull,
Perfect For Revision
It was really helpful perfect for revision.
wow i really like this important question for me SA -2 exam
THANKU BYJU’S TEAM FOR GIVING THIS IMPOTANT PAPER