CBSE Class 9 Maths Chapter 11 important questions for Chapter 11 Constructions with solutions are available for students to prepare for theÂ **exam 2020-21**. These questions are presented by our expert teachers in accordance with **CBSE(NCERT)** curriculum. Practising these questions will help students to score well in the upcoming examination, as they get more familiar with the question types asked in the exam.

Students can do the revision with the help of important questions for CBSE Class 9 Maths, given for each chapter here at BYJUâ€™S. In this chapter-Construction, step-by-step procedure is explained to guide students to understand well. Students can at first try solving the questions themselves, and then they can refer to the answers to self-analyse their performance.

**Also Check:**

- Important 2 Marks Questions for CBSE 9th Maths
- Important 3 Marks Questions for CBSE 9th Maths
- Important 4 Marks Questions for CBSE 9th Maths

## Important Questions & Solutions For Class 9 Maths Chapter 11 (Constructions)

**Q.1: Construct an equilateral triangle, given its side 4cm and justify the construction.**

Solution:

Construction Procedure:

- Let draw a line segment AB=4 cm .
- With A and B as centres, draw two arcs on the line segment AB and note the point as D and E.
- With D and E as centres, draw the arcs that intersect the previous arc respectively that forms an angle of 60Â° each.
- Now, draw the lines from A and B that are extended to meet each other at point C.
- Therefore, ABC is the required triangle.

**Justification:**

From construction, it is observed that

AB = 4 cm, âˆ A = 60Â° and âˆ B = 60Â°

We know that, the sum of the interior angles of a triangle is equal to 180Â°

âˆ A + âˆ B + âˆ C = 180Â°

SuBstitute the values

â‡’ 60Â° + 60Â° + âˆ C = 180Â°

â‡’ 120Â° + âˆ C = 180Â°

â‡’ âˆ C = 60Â°

While measuring the sides, we get

BC = CA = 4 cm (Sides opposite to equal angles are equal)

AB = BC = CA = 4 cm

âˆ A = âˆ B = âˆ C = 60Â°

Hence, justified.

**Q.2: Construct a triangle ABC in which BC = 7cm, âˆ B = 75Â° and AB + AC = 13 cm.**

Solution:

Construction Procedure:

The steps to draw the triangle of given measurement is as follows:

- Draw a line segment of base BC = 7 cm
- Measure and draw âˆ B = 75Â° and draw the ray BX
- Take a compass and measure AB + AC = 13 cm.
- With B as a centre and draw an arc at the point be D
- Join DC
- Now draw the perpendicular bisector of the line BD and the intersection point is taken as A.
- Now join AC
- Therefore, ABC is the required triangle.

**Q.3: Construct a triangle XYZ in which âˆ Y = 30Â°, âˆ Z = 90Â° and XY + YZ + ZX = 11 cm.**

Solution:

**Construction Procedure:**

The steps to draw the triangle of given measurement is as follows:

- Draw a line segment AB which is equal to XY + YZ + ZX = 11 cm.
- Make an angle âˆ Y = 30Â° from point A and the angle be âˆ LAB
- Make an angle âˆ Z = 90Â° from point B and the angle be âˆ MAB
- Bisect âˆ LAB and âˆ MAB at point X.
- Now take the perpendicular bisector of the line XA and XB and the intersection point be Y and Z respectively.
- Join XY and XZ
- Therefore, XYZ is the required triangle

**Q.4: Construct a triangle ABC in which BC = 8cm, âˆ B = 45Â° and AB â€“ AC = 3.5 cm.**

Solution:

Construction Procedure:

The steps to draw the triangle of given measurement is as follows:

- Draw a line segment of base BC = 8 cm
- Measure and draw âˆ B = 45Â° and draw the ray BX
- Take a compass and measure AB â€“ AC = 3.5 cm.
- With B as centre and draw an arc at the point be D on the ray BX
- Join DC
- Now draw the perpendicular bisector of the line CD and the intersection point is taken as A.
- Now join AC
- Therefore, ABC is the required triangle.

**Q.5: Draw a line segment AB of 4 cm in length. Draw a line perpendicular to AB through A and B, respectively. Are these lines parallel?**

Solution:

According to the question,

A line segment AB of length 4cm.

To draw a perpendicular to AB through A and B, respectively.

Steps of construction:

1. Draw AB = 4 cm.

2. With A as centre, draw an arc, intersecting AB at P.

3. With P as centre and the same radius, draw an arc intersecting the arc drawn in step 2 at Q.

4. With Q as centre and the same radius, draw an arc, intersecting the arc drawn in step 3 at R.

5. With R as centre and the same radius, draw an arc, intersecting the arc drawn in step 5 at X.

6. Draw OX and produced it to C and D.

7. Now, repeat the steps from 2 to 7 to draw the line EF perpendicular through B.

Yes, these lines are parallel because the sum of the interior angles on the same side of the transversal is 180 degrees.

### Extra Questions To Practice For Class 9 Maths Chapter 11 (CBSE)

- Construct a triangle PQR in which QR = 6cm, âˆ Q = 60Â° and PR â€“ PQ = 2cm.
- Construct a right triangle whose base is 12cm and sum of its hypotenuse and other side is 18 cm.
- Draw an angle of 80Â° with the help of a protractor. Then construct angles of
- (i) 40Â°
- (ii)160Â°
- (iii) 120Â°

- Construct a triangle whose sides are 3.6 cm, 3.0 cm and 4.8 cm. Bisect the smallest angle and measure each part.
- A triangle if its perimeter is 10.4 cm and two angles are 45Â° and 120Â°.
- Construct a triangle PQR such that QR= 6 cm, PQ=6 cm and PS=4cm.