Remainder Theorem

A Remainder Theorem is an approach of Euclidean division of polynomials. “It is applied to factorize polynomials of each degree in swift and elegant manner. Theorem implies that after you divide a polynomial P(x) by a factor ( x – a); that isn’t essentially an element of the polynomial; you will find a smaller polynomial along with a remainder. This remainder that has been obtained is actually a value of P(x) at x = a, specifically P(a)  “.

Remainder Theorem And Polynomials

Theorem functions on an actual case that a polynomial is comprehensively dividable, at least one time by its factor in order to get a smaller polynomial and ‘a’ remainder of zero. This acts as one of the simplest way to determine whether the value ‘a’ is a root of the polynomial P(x).

That is when we divide p(x) by x-a we obtain

p(x) = (x-a)·q(x) + r(x),

as we know that Dividend = (Divisor × Quotient) + Remainder

But if r(x) is simply the constant r (remember when we divide by (x-a) the remainder is a constant)…. so we obtain the following solution, i.e

p(x) = (x-a)·q(x) + r

Observe what happens when we have x equal to a:

p(a) = (a-a)·q(a) + r

p(a) = (0)·q(a) + r

p(a) = r

Remainder Theorem Examples

Consider the following example:-

Example- Determine that x = 1 is a root of P(x),

Explanation:

It suggest that x = 1 may be a root of P(x), and (x – 1) may be a factor of P(x)

Then if we tend to divide synthetically from P(x) by (x – 1), we will get a new smaller polynomial and a remainder of zero:

Factor Theorem

Factor Theorem is generally applied to factorizing and finding the roots of polynomial equations. It is the reversal form of remainder theorem. Problems are solved based on the application of synthetic division and then to check for a zero remainder.

When p(x) = 0 then y-x is a factor of the polynomial Or if we consider the other way, then When y-x is a factor of the polynomial then p(x) =0

Example: Find the root of the polynomial \(x^{2}- 3x – 4\).

Solution: \( x^{2} – 3x – 4\)

\( f(4) = 4^{2} – 3(4) – 4\)

\( f(4) = 16 – 16 = 0\)

So,  (x-4) must be a factor of \( x^{2} – 3x – 4\)

Example: Find the remainder when\(t^{3} – 2t^{2} + t + 1\) is divided by t – 1.

Solution: Here, \(p(t) = t^{3} – 2t^{2} + t + 1\), and the zero of t – 1 is 1.

∴ p (1) = (1)3 – 2(1)2 + 1 + 1= 2

By the Remainder Theorem, 2 is the remainder when \(t^{3} – 2t^{2} + t + 1\) is divided by t – 1.

Euler Remainder Theorem

Euler’s theorem  states that if n and X are two co-prime positive integers, then

\(X^{φ(n)} = 1 (mod \; n)\)

where, \(φ(n)\) is Euler’s function.

where φ(n) is Euler’s totient function and

\( φ(n) = n \left ( 1- \frac{1}{a} \right ) . \left ( 1- \frac{1}{b} \right ) . \left ( 1- \frac{1}{c} \right )\)

where, n is a natural number, such that n = \(a^{p}. b ^{q} . c^{r}\),

here, a, b, c are prime factors of n and p, q, r are positive integers.

Example: Find the Euler totient function of 35.

Solution: The factors of 35 are as follows:

\(35 = 5 \times 7\)

\( φ(35) = 35 \left ( 1 – \frac{1}{5} \right ) . \left ( 1 – \frac{1}{7} \right ) = 24  \)

Thus the totient function of 35 is 24.

Questions of the form: \(\large \mathbf{\frac{m^{a}}{n}}\)

Example: Find the remainder when \(3^{76}\) is divided by 35.

Solution: Here m = 3, a = 76 and n = 35,

In an example above we have already found the totient function of 35, which is equal to 24.

Remainder of \(\frac{76}{φ(35)} = \frac{76}{24}\) = 4

Remaining power is 4, which when divided by 35 given the resultant remainder.

which is, \(\frac{3^{4}}{35} = \frac{81}{35} = 11\)<

Thus the remainder comes out to be 11.

This was all about remainder theorem . To learn more about number system, visit BYJU’S- The learning app.


Practise This Question

Given P = Product of x2 y and xy and Q = Quotient obtained when x2 is divided by D. If P = Q, what is the value of D?