# Vertical Angles (Vertically Opposite Angles)

When two lines intersect each other, then the opposite angles, formed due to intersection are called vertical angles or vertically opposite angles. A pair of vertically opposite angles are always equal to each other. When two lines meet at a point in a plane, they are known as intersecting lines. When the lines do not meet at any point in a plane, they are called parallel lines. Learn about Intersecting Lines And Non-intersecting Lines here.

The given figure shows intersecting lines and parallel lines.

In the figure given above, the line segment $\overline{AB}$ and $\overline{CD}$ meet at the point $O$ and these represent two intersecting lines. The line segment $\overline{PQ}$ and $\overline{RS}$ represent two parallel lines as they have no common intersection point in the given plane.

In a pair of intersecting lines, the angles which are opposite to each other form a pair of vertically opposite angles. In the figure given above, ∠AOD and ∠COB form a pair of vertically opposite angle and similarly ∠AOC and ∠BOD form such a pair. Therefore,

∠AOD = ∠COB

∠AOC = ∠BOD

For a pair of opposite angles the following theorem, known as vertical angle theorem holds true.

## Vertical Angles: Theorem and Proof

Theorem: In a pair of intersecting lines the vertically opposite angles are equal.

Proof: Consider two lines $\overleftrightarrow{AB}$ and $\overleftrightarrow{CD}$ which intersect each other at $O$. The two pairs of vertical angles are:

i) ∠AOD and ∠COB

ii) ∠AOC and ∠BOD

It can be seen that ray $\overline{OA}$ stands on the line $\overleftrightarrow{CD}$ and according to Linear Pair Axiom, if a ray stands on a line, then the adjacent angles form a linear pair of angles.

Therefore, ∠AOD + ∠AOC = 180° —(1) (Linear pair of angles)

Similarly, $\overline{OC}$ stands on the line $\overleftrightarrow{AB}$.

Therefore, ∠AOC + ∠BOC = 180° —(2) (Linear pair of angles)

From (1) and (2),

∠AOD + ∠AOC = ∠AOC + ∠BOC

⇒ ∠AOD = ∠BOC —(3)

Also, $\overline{OD}$ stands on the line $\overleftrightarrow{AB}$.

Therefore, ∠AOD + ∠BOD = 180° —(4) (Linear pair of angles)

From (1) and (4),

∠AOD + ∠AOC = ∠AOD + ∠BOD

⇒ ∠AOC = ∠BOD —(5)

Thus, the pair of opposite angles are equal.

Hence, proved.

### Example

Consider the figure given below to understand this concept.

In the given figure ∠AOC = ∠BOD and ∠COB = ∠AOD(Vertical Angles)

⇒ ∠BOD = 105° and ∠AOD = 75°

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