Class 10 Maths Chapter 2 Polynomials MCQs

We have provided here MCQs for Class 10 Maths chapter Polynomials online, along with answers. These objective questions have been prepared, as per the CBSE syllabus and NCERT curriculum. Practising these multiple choice questions will help students to score better marks in the board exams. It will help them to increase their problem solving skills. To practice MCQs for all the chapters, click here.

Class 10 Maths MCQs for Polynomials

MCQs for polynomials are given here for Class 10 students and they are advised to solve these questions as per their knowledge and skills. Later, they can verify their answers with the help of detailed explanations given here. Get important questions for class 10 Maths here at BYJU’S.

Below are the MCQs for Chapter 2-Polynomials

1.The zeroes of x2–2x –8 is:

 

(a)(2,-4)

(b)(4,-2)

(c)(-2,-2)

(d)(-4,-4)

Answer: (b)

Explanation: x2–2x –8 = x2–4x + 2x –8 = x(x–4)+2(x–4) = (x-4)(x+2)

x = 4, -2.

2. What is the quadratic polynomial for the zeroes √2, ⅓.

(a)3x2-3√2x+1 = 0

(b)3x2+3√2x+1 = 0

(c)3x2+3√2x-1 = 0

(d)None of the above

Answer: (a)

Explanation: Sum of zeroes = α + β =√2

Product of zeroes = α β = 1/3

∴ If α and β are zeroes of any quadratic polynomial, then;

x2–(α+β)x +αβ = 0

x2 –(√2)x + (1/3) = 0

3x2-3√2x+1 = 0

3. If the zeroes of the quadratic polynomial ax2+bx+c, c≠0 are equal, then

 

(a)c and b have opposite signs

(b)c and a have opposite signs

(c)c and b have same signs

(d)c and a have same signs

Answer: (d)

Explanation:

For equal roots, discriminant will be equal to zero.

b2 -4ac = 0

b2 = 4ac

ac = b2/4

ac>0 (as square of any number cannot be negative)

4. The degree of the polynomial, x4 – x2 +2 is

 

(a)2

(b)4

(c)1

(d)0

Answer: b

Explanation: Degree is the highest power of the variable in any polynomial.

5. If one of the zeroes of cubic polynomial is x3+ax2+bx+c is -1, then product of other two zeroes is:

 

(a)b-a-1

(b)b-a+1

(c)a-b+1

(d)a-b-1

Answer: (b)

Explanation: Since one zero is -1, hence;

P(x) = x3+ax2+bx+c

P(-1) = (-1)3+a(-1)2+b(-1)+c

0 = -1+a-b+c

c=1-a+b

Product of zeroes, αβγ = -constant term/coefficient of x3

(-1)βγ = -c/1

c=βγ

βγ = b-a+1

6. If p(x) is a polynomial of degree one and p(a) = 0, then a is said to be:

 

(a)Zero of p(x)

(b)Value of p(x)

(c)Constant of p(x)

(d)None of the above

Answer: (a)

Explanation: Let p(x) = mx+n

Put x = a

p(a)=ma+n=0

So, it shows a is zero of p(x).

7. Zeroes of a polynomial can be expressed graphically. Number of zeroes of polynomial is equal to number of points where the graph of polynomial is:

(a)Intersects x-axis

(b)Intersects y-axis

(c)Intersects y-axis or x-axis

(d)None of the above

Answer: (a)

8. A polynomial of degree n has:

 

(a)Only one zero

(b)At least n zeroes

(c)More than n zeroes

(d)Atmost n zeroes

Answer: (d)

Explanation: Maximum number of zeroes of a polynomial = Degree of the polynomial

9. The number of polynomials having zeroes as -2 and 5 is:

(a)1

(b)2

(c)3

(d)More than 3

Answer: (d)

Explanation: The polynomials x2-3x-10, 2x2-6x-20, 1/2x2-3/2x-5, 3x2-9x-30, have zeroes as -2 and 5.

10. Zeroes of p(x) = x2-27 are:

(a)±9√3

(b)±3√3

(c)±7√3

(d)None of the above

Answer: b

Explanation: x2-27 = 0

x2=27

x=√27

x=±3√3

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