**Class 10 Maths MCQs for Chapter** 8 (Introduction to trigonometry) are given here with answers and detailed explanations. All these multiple-choice questions are available online as per the CBSE syllabus and NCERT guidelines. Solving these objective questions will help students to score better marks in the board exam.

## Class 10 Maths MCQs for Introduction to Trigonometry

Practice the MCQs for Chapter 8, introduction to the trigonometry of Class 10 Maths and verify your answers. Also, find important questions for class 10 Maths here to practice more.

**1. In ∆ ABC, right-angled at B, AB = 24 cm, BC = 7 cm. The value of tan C is:**

(a)12/7

(b)24/7

(c)20/7

(d)7/24

Answer: (b)

Explanation: AB=24cm and BC = 7cm

Tan C = Opposite side/Adjacent side

Tan C=24/7

**2. (Sin 30°+cos 60°)-(sin 60° + cos 30°) is equal to:**

(a)0

(b)1+2√3

(c)1-√3

(d)1+√3

Answer: c

Explanation: sin 30° = ½, sin 60° = √3/2, cos 30° = √3/2 and cos 60° = ½

Putting these values, we get:

(½+½)-(√3/2+√3/2)

= 1-√3

**3. The value of tan 60°/cot 30° is equal to:**

(a)0

(b)1

(c)2

(d)3

Answer: b

Explanation: tan 60° = √3 and cot 30° = √3

Hence, tan 60°/cot 30° = √3/√3 = 1

**4. 1-cos ^{2}A is equal to:**

(a)sin^{2}A

(b)tan^{2}A

(c)1-sin^{2}A

(d)sec^{2}A

Answer: a

Explanation: We know, by trigonometry identities,

sin^{2}A+cos^{2}A = 1

1-cos^{2}A = sin^{2}A

**5. Sin (90° – A) and cos A are:**

(a)Different

(b)Same

(c)Not related

(d)None of the above

Answer: b

Explanation: By trigonometry identities.

Sin (90°-A) = cos A [comes in the first quadrant of unit circle]

**6. If cos X = ⅔ then tan X is equal to:**

(a)5/2

(b)√(5/2)

(c)√5/2

(d)2/√5

Answer: (c)

Explanation: By trigonometry identities, we know:

1+tan^{2}X=sec^{2}X

And sec X = 1/cos X = 1/(⅔) = 3/2

Hence,

1+tan^{2}X=(3/2)^{2}=9/4

tan^{2}X=9/4-1=5/4

Tan X = √5/2

**7. If cos X=a/b, then sin X is equal to:**

(a)b^{2}-a^{2}/b

(b)b-a/b

(c)√(b^{2}-a^{2})/b

(d)√(b-a)/b

Answer: (c)

Explanation: cos X=a/b

By trigonometry identities, we know that:

sin^{2}X+cos^{2}X=1

sin^{2}X=1-cos^{2}X = 1-(a/b)^{2}

Sin X=√(b^{2}-a^{2})/b

**8. The value of sin 60° cos 30° + sin 30° cos 60° is:**

(a)0

(b)1

(c)2

(d)4

Answer: b

Explanation: sin 60° = √3/2, sin 30° = ½, cos 60° = ½ and cos 30° = √3/2

Therefore,

√3/2 x √3/2 + ½ x ½

= 3/4 + 1/4

= 1

**9. 2tan 30°/1+tan ^{2}30° =**

(a)Sin 60°

(b)Cos 60°

(c)Tan 60°

(d)Sin 30°

Answer: a

Explanation: tan 30° = 1/√3

Putting this value we get;

2(1/√3)/1+(1/√3)^{2} = (2/√3)/4/3 = 6/4√3 = √3/2 = sin 60°

**10. sin 2A = 2 sin A is true when A =**

(a)30°

(b)45°

(c)0°

(d)60°

Answer: (c)

Explanation: sin 2A = sin 0° = 0

2sin A = 2sin 0° = 0