Class 8 Maths Chapter 10 (Visualising Solid Shapes) MCQs are available online with solved answers. These objective questions are formulated by experts, according to the latest CBSE syllabus (2020-2021) and NCERT curriculum. The chapter-wise multiple-choice questions are given at BYJU’S to make students learn each topic and help them to score good marks in exams. Also, learn important questions for class 8 Maths here.
MCQs on Class 8 Visualising Solid Shapes
Multiple choice questions (MCQs) are given for Class 8 Visualising Solid Shapes chapter. All questions here will be provided with four multiple choices, among which one is the right answer.
1. A cube has ______ faces.
A. 4
B. 5
C. 6
D. 8
Answer: C
Explanation: A cube is a three dimensional shape having six faces.
2. Number of vertices a cone has:
A.One
B. Two
C. Three
D. Four
Answer: A
3. A sphere has how many faces?
A. One
B. Two
C. Four
D. None
Answer: D
Explanation: A sphere is a round-shaped object having no faces and edges.
4. An example of cone is:
A. Tube
B. A tent
C. A ball
D. A box
Answer: B
5. The top-view of a cone looks like:
A. A Circle
B. A Square
C. A Rectangle
D. A Triangle
Answer: A
Explanation: The base of a right-cone is always circular. When we see it from the top, it looks like a circle with its vertex as the center of the circle.
6. The top-view of a cube looks like a:
A. Circle
B. Square
C. Rectangle
D. Triangle
Answer: B
Explanation: Since all the faces of a cube are of equal length.
7. The top-view of a cuboid looks like a:
A. Circle
B. Square
C. Rectangle
D. Triangle
Answer: C
8. The side-view of a cone appears as:
A. Circle
B. Square
C. Rectangle
D. Triangle
Answer: D
9. The base of a prism is:
A. Circle
B. Triangle
C. Square
D. Any shape
Answer: D
Explanation: A pyramid is a polyhedron whose base is a polygon (of any number of sides) and whose lateral faces are triangles with a common vertex.
10. If a polyhedron has 6 vertices and 12 edges. What is the number of faces it has?
A. 6
B. 8
C. 12
D. 18
Answer: B
Explanation: By Euler’s formula we know that:
For any polyhedron,
F + V – E = 2
F = 2-V+E
F = 2 – 6+12 = 8
