**Important questions for Class 8 chapter 3 – Understanding quadrilaterals** are given here. Students who are preparing for final exams can practice these questions to score good marks. All the questions presented here are as per NCERT curriculum or CBSE syllabus.

Understanding quadrilaterals chapter deals with different types of quadrilaterals and their properties. You will also learn to compute the measure of any missing angle of quadrilateral. Let us see some important questions with solutions here.

Students can also reachÂ Important Questions for Class 8 MathsÂ to get important questions for all the chapters here.

## Class 8 Chapter 3 Important Questions

Questions and answers are given here based on important topics of class 8 Maths Chapter 3.

**Q.1: A quadrilateral has three acute angles, each measure 80Â°. What is the measure of the fourth angle?**

Solution:

Let x be the measure of the fourth angle of a quadrilateral.

Sum of the four angles of a quadrilateral = 360Â°

80Â° + 80Â° + 80Â° + x = 360Â°

x = 360Â° – (80Â° + 80Â° + 80Â°)

x = 360Â° – 240Â°

x = 120Â°

Hence, the fourth angle is 120Â°.

**Q,2: In a quadrilateral ABCD, the measure of the three angles A, B and C of the quadrilateral is 110Â°, 70Â° and 80Â°, respectively. Find the measure of the fourth angle.**

Solution: Let,

âˆ A = 110Â°

âˆ B = 70Â°

âˆ C = 80Â°

âˆ D = x

We know that the sum of all internal angles of quadrilateral ABCD isÂ 360Â°.

âˆ A + âˆ B+ âˆ C+âˆ D = 360Â°

110Â°Â + 70Â°Â + 80Â°Â + xÂ = 360Â°

260Â° + x = 360Â°

x = 360Â° – 260Â°

x = 100Â°

Therefore, the fourth angle is 100Â°.

**Q.3: In a quadrilateral ABCD,Â âˆ D is equal to 150Â° andÂ âˆ A =Â âˆ B =Â âˆ C. FindÂ âˆ A,Â âˆ B andÂ âˆ C.**

Solution: Given,

âˆ D = 150Â°

LetÂ âˆ A =Â âˆ B =Â âˆ C = x

By angle sum property of quadrilateral,

âˆ A + âˆ B + âˆ C +Â âˆ D = 360Â°

x + x +x+âˆ D = 360Â°

3x+âˆ D = 360Â°

3x = 360Â° –Â âˆ D

30 = 360Â° – 150Â°

3x = 210Â°

x = 70Â°

Hence,Â âˆ A =Â âˆ B =Â âˆ C = 70Â°.

**Q.4: The angles of a quadrilateral are in the ratio of 1 : 2 : 3 : 4. What is the measure of the four angles?**

Solution: Given,

The ratio of the angles of quadrilaterals = 1 : 2 : 3 : 4

Let the four angles of the quadrilateral be x, 2x, 3x, and 4x respectively.

The sum of four angles of a quadrilateral is 360Â°.

Therefore,

x + 2x + 3x + 4x = 360Â°

10x = 360Â°

x = 360Â°/10

x = 36Â°

Therefore,

First angle = x = 36Â°

Second angle = 2x = 2Â Ã— 36 = 72Â°

Third angle = 3x = 3Â Ã— 36 = 108Â°

Fourth angle = 4x = 4Â Ã— 36 = 144Â°

Hence, the measure of four angles is 36Â°,Â 72Â°, 108Â° and 144Â°.

**Q. 5: In quadrilaterals,Â **

**(i) which of them have their diagonals bisecting each other?**

**(ii) which of them have their diagonal perpendicular to each other?**

**(iii) which of them have equal diagonals?**

Solution:

(i) Diagonals bisect each other in:

- Parallelogram
- Rhombus
- Rectangle
- Square
- Kite

(ii) Diagonals are perpendicular in:

- Rhombus
- Square
- Kite

(iii) Diagonals are equal to each other in:

- Rectangle
- Square

**Q. 6: Adjacent sides of a rectangle are in the ratio 5 : 12, if the perimeter of the rectangle is 34 cm, find the length of the diagonal.**

Solution:

Given,

Ratio of the adjacent sides of the rectangle = 5 : 12

Let 5x and 12x be the two adjacent sides.

We know that the sum of all sides of a rectangle is equal to its perimeter.

Thus,

5x + 12x + 5x + 12x = 34 cm (given)

34x = 34

x = 34/34

x = 1 cm

Therefore, the adjacent sides are 5 cm and 12 cm respectively.

i.e. l = 12 cm, b = 5 cm

Length of the diagonal = âˆš(l^{2} + b^{2})

= âˆš(12^{2} + 5^{2})

= âˆš(144 + 25)

= âˆš169

= 13 cm

Hence, the length of the diagonal is 13 cm.

**Q. 7: The opposite angles of a parallelogram are (3x + 5)Â° and (61 – x)Â°. Find the measure of four angles.**

Solution:

Given,

(3x + 5)Â° and (61 – x)Â° are the opposite angles of a parallelogram.

We know that the opposite angles of a parallelogram are equal.

Therefore,

(3x + 5)Â° = (61 – x)Â°

3x + x = 61Â° – 5Â°

4x = 56Â°

x = 56Â°/4

x = 14Â°

â‡’ 3x + 5 = 3(14) + 5 = 42 + 5 = 47

61 – x = 61 – 14 = 47

The measure of angles adjacent to the given angles = 180Â° – 47Â° = 133Â°

Hence, the measure of four angles of the parallelogram are 47Â°, 133Â°, 47Â°, and 133Â°.

**Q. 8: ABCD is a parallelogram with âˆ A = 80Â°. The internal bisectors of âˆ B and âˆ C meet each other at O. Find the measure of the three angles of Î”BCO.**

Solution:

Given,

âˆ A = 80Â°

We know that the opposite angles of a parallelogram are equal.

âˆ A = âˆ C = 80Â°

And

âˆ OCB = (1/2) Ã— âˆ C

= (1/2) Ã— 80Â°

= 40Â°

âˆ B = 180Â° – âˆ A (the sum of interior angles on the same side of the transversal is 180)

= 180Â° – 80Â°

= 100Â°

Also,

âˆ CBO = (1/2) Ã— âˆ B

= (1/2) Ã— 100Â°

= 50Â°

By the angle sum property of triangle BCO,

âˆ BOC + âˆ OBC + âˆ CBO = 180Â°

âˆ BOC = 180Â° – (âˆ OBC + CBO)

= 180Â° – (40Â° + 50Â°)

= 180Â° – 90Â°

= 90Â°

Hence, the measure of all the three angles of a triangle BCO is 40Â°, 50Â° and 90Â°.

**Q. 9: Find the measure of all four angles of a parallelogram whose consecutive angles are in the ratio 1 : 3.**

Solution:

Given,

The ratio of two consecutive angles of a parallelogram = 1 : 3

Let x and 3x be the two consecutive angles.

We know that the sum of interior angles on the same side of the transversal is 180Â°.

Therefore, x + 3x = 180Â°

4x = 180Â°

x = 180Â°/4

x = 45Â°

â‡’ 3x = 3(45Â°) = 135Â°

Thus, the measure of two consecutive angles is 45Â° and 135Â°.

As we know, the opposite angles of a parallelogram are equal.

Hence, the measure of all the four angles is 45Â°, 135Â°, 45Â°, and 135Â°.

**Q. 10: A diagonal and a side of a rhombus are of equal length. Find the measure of the angles of the rhombus.**

Solution:

Let ABCD be the rhombus.

Thus, AB = BC = CD = DA

Given that a side and diagonal are equal.

AB = BD (say)

Therefore, AB = BC = CD = DA = BD

Now, all the sides of a triangle ABD are equal.

Therefore, Î”ABD is an equilateral triangle.

Similarly,

Î”BCD is also an equilateral triangle.

Thus, âˆ A = âˆ ABD = âˆ ADB = âˆ DBC = âˆ C = âˆ CDB = 60Â°

âˆ B = âˆ ABD + âˆ DBC = 60Â° + 60Â° = 120Â°

And

âˆ D = âˆ ADB + âˆ CDB = 60Â° + 60Â° = 120Â°

Hence, the angles of the rhombus are 60Â°, 120Â°, 60Â° and 120Â°.

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