Conformal mapping is a function defined on the complex plane which transforms a given curve or points on a plane, preserving each angle of that curve. If f(z) is a complex function defined for all z in C, and w = f(z), then f is known as a transformation which transforms the point z = x + iy in z-plane to w = u + iv in w-plane. If this transformation preserves the angles between curves in both magnitude and sense (clockwise or counterclockwise), then the mapping is called conformal mappings.
If there is a transformation such that the magnitude of the angles between the curves is identical, but the sense (clockwise or counterclockwise) is opposite. In that case, the transformation is called isogonal.
Definition of Conformal Mapping
Consider the transformations u = u(x, y) and v = v(x, y), which maps a point P(xo, yo) in the z-plane to a point P’(uo, vo) in the w-plane. Let curves C1 and C2 intersect at point zo = (xo, yo) in z-plane is mapped into curves C1’ and C2’ in w-plane intersecting at wo = (uo, vo).
If the transformation is such that the angle between C1 and C2 at zo is equal both in magnitude and sense to the angle between the curve C1’ and C2’ at wo, it is known as conformal mapping at zo = (xo, yo).
Note: i) The scaling factor and the rotation angle for a given transformation f(z) depend only on z and not on curves passing through z. ii) Conformality depends on the given point. It is different at various points in the plane. |
Conditions for Conformal Mapping
The sufficient condition for a transformation w = f(z) to be a conformal mapping is:
Let f(z) be an analytic function of z in a domain D of the z-plane and let f’(z) ≠ 0 inside D. Then the mapping w = f(z) is conformal at all points of D. |
The necessary condition for a transformation being a conformal mapping is:
If w = f(z) represents a conformal transformation of a domain D of z-plane into a domain D’ of w-plane, then f(z) is an analytic function of z in D’. |
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Solved Examples on Conformal Mappings
Example 1:
Given transformation w = f(z) = z2, which lies in the area in the first quadrant of the z-plane bounded by the axes and circles |z| = a and |z| = b, where (a > b > 0). Discuss the transformation in the w-plane and check whether it is a conformal mapping.
Solution:
The given transformation w = z2
Let z = rei𝜃 and w = Reiϕ. Then we have
Reiϕ = r2ei2𝜃 that is,
R = r2 and ϕ = 2𝜃
Now, the circle |z| = r = a, 0 ≤ 𝜃 ≤ 𝜋/2 in the z-plane is transformed into a semicircle
|w| = R = a2, 0 ≤ ϕ ≤ 𝜋 (since R = r2 and ϕ = 2𝜃)
in the w-plane.
Similarly, the quadrant |z| = r = b, 0 ≤ 𝜃 ≤ 𝜋/2 in the z-plane is transformed into a semicircle
|w| = R = b2, 0 ≤ ϕ ≤ 𝜋 (since R = r2 and ϕ = 2𝜃)
in w-plane.
This shows that the annular region between the circles |z| = a and |z| = b in the first quadrant of z-plane is transformed into the annular region between |w| = a2 and |w| = b2 in the upper half-plane of the w-plane as shown in the figure.
Let us check for the conformality for the given transformation.
Differentiating both sides of w = z2 with respect to z, we have
dw/dz = 2z ≠ 0 for any z in the given region.
Thus, the given transformation is a conformal mapping.
Example 2:
Show that the transformation w = (2/√z) – 1 transforms the region outside the parabola
y2 = 4(1 – x) into the interior of the unit circle in the w-plane.
Solution:
The given transformation w = (2/√z) – 1 ⇒ (w + 1)2 = 4/z ….(1)
If |w| = 1 be the unit circle in the w-plane, the let w = eiϕ. Thus by the given transformation (1) we have,
(eiϕ + 1)2 = 4/rei𝜃 where z = rei𝜃
Or, 1 + eiϕ = (2/√r)e-i𝜃/2 ……….(2)
Now, eiϕ = cos ϕ + i sin ϕ and e-i𝜃/2 = cos 𝜃/2 – i sin 𝜃/2
Equating real and imaginary parts of both sides in (2)
1 + cos ϕ = (2/√r) cos 𝜃/2 and sin ϕ = –(2/√r) sin 𝜃/2
cos2 ϕ + sin2 ϕ = [(2/√r) cos 𝜃/2 – 1]2 + (4/r) sin2 𝜃/2
⇒ 4/r – (4/√r) cos 𝜃/2 = 0
That is, 1/r = cos2 𝜃/2 or 2/r = 1 + cos 𝜃 ………..(3)
The equation (3) represents a parabola in the z-plane.
Now for the interior points of the unit circle |w| = 1, we have w = aeiϕ (a < 1). Substituting this in (1), we get
(aeiϕ + 1)2 = 4/rei𝜃 or 1 + aeiϕ = (2/√r)e-i𝜃/2
Again, equating the real and imaginary parts on both the sides
1 + a cos ϕ = (2/√r) cos 𝜃/2 and a sin ϕ = –(2/√r) sin 𝜃/2
Then, a2 = [(2/√r) cos 𝜃/2 – 1]2 + (4/r) sin2 𝜃/2
Or, 4/r – (4/√r) cos 𝜃/2 = a2 – 1 < 0 as a < 1
Or, 1/√r < cos 𝜃/2
Or, r > 2/(1 + cos 𝜃)
which shows that the point (r, 𝜃) lies outside the parabola. Hence, the exterior of the parabola corresponds to the interior of the unit circle in the w-plane.
Frequently Asked Questions on Conformal Mapping
What is meant by conformal mapping?
Conformal mapping is a function defined on the complex plane which transforms a given curve, preserving each angle of that curve.
What is the necessary condition for a conformal mapping?
The necessary condition for a conformal mapping is that if w = f(z) represents a conformal transformation of a domain D of z-plane into a domain D’ of w-plane, then f(z) is an analytic function of z in D’.
What is the sufficient condition for a transformation to be a conformal mapping?
The sufficient condition for a transformation to be a conformal mapping is that if f(z) be an analytic function of z in a domain D of the z-plane and if f’(z) ≠ 0 inside D. Then the mapping w = f(z) is conformal at all points of D.
What is the other name for conformal mappings?
Conformal mappings are also known as angle-preserving transformations.
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