The perimeter questions and answers provided in this article can help students grasp the topic quickly. Perimeter is one of the most basic concepts taught in elementary and secondary school. To frame the questions, the NCERT curriculum is used. These questions can be used by students to acquire a quick overview of the concepts and to practise them so that they are more familiar with the topic. Refer to the detailed explanations provided for each question to double-check your answers. For more information on the perimeter, click here.
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Perimeter Definition: The complete distance around a shape is referred to as its perimeter. In simple terms, the perimeter of any shape is its length when expanded in a linear form. In a two-dimensional plane, a perimeter is the total distance that encircles a shape. Perimeter is expressed in units, such as centimetres, inches, feet, and other units. |
Read and practise the perimeter questions and answers listed below.
Perimeter Questions with Solutions
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Perimeter Formulas: The perimeter formulas for all 2d-shapes are listed here. Circle – 2πr units, where “r” is the radius of the circle Triangle – a+b+c units, where a,b and c are the triangle sides Square – 4a units, where a is the side length of square Rectangle – 2(l+b) units, where l and b are the length and breadth of a rectangle Parallelogram – 2(a+b) units, where a and b are adjacent sides of a parallelogram Quadrilateral – Sum of all four sides Any Polygon – Sum of all the sides Also, read: Perimeter of Different Shapes. |
1. What is the perimeter of a rectangle, if its length and breadth are 36m and 24m, respectively?
Solution:
Given, length, l = 36 m
Breadth, b = 24 m.
We know that the perimeter of a rectangle = 2(l+b) units
P = 2(36+ 24) m
P = 2(60) m
P = 120 m
Hence, the perimeter of the rectangle is 120 m.
2. Find the perimeter of a circle whose diameter is 14 cm. [Note: Take π = 3.14]
Solution:
Given, diameter = 14 cm
Hence, radius, r = 14/2 = 7 cm
As we know, the perimeter of a circle = 2πr units
P = 2(3.14)(7)
P = 14(3.14)
P = 43.96
Thus, the perimeter/circumference of the circle = 43.96 cm.
3. Find the breadth of the rectangular field, if its perimeter is 240 m and length is 90 m.
Solution:
Given, perimeter, P = 240 m
Length, l = 90 m
We know that, perimeter of the rectangle = 2(l+b) units
Now, substitute the known values in the formula, we get
240 = 2(90 + b)
240 = 180 + 2b
2b = 240 – 180
2b = 60
b = 60/2 = 30 m
Hence, the breadth of the rectangular field is 30 m.
Read: Perimeter of a Rectangle.
4. Find the perimeter of an equilateral triangle, whose side length is 3 cm.
Solution:
In an equilateral triangle, all the sides are equal in length.
If a, b and c are the sides of an equilateral triangle, then we can write
a = b = c = 3 cm
Since, perimeter of a triangle is a+b+c units, the perimeter of the equilateral triangle = 3 + 3 + 3 cm
Hence, the perimeter of the equilateral triangle = 9 cm.
5. Compute the perimeter of a square, whose side length is 15 cm.
Solution:
Given, the side length of a square, a = 15 cm
We know that the perimeter of a square, P = 4a units
P = 4(15) = 60 cm
Thus, the perimeter of the square is 60 cm.
6. Determine the perimeter of a regular pentagon whose side measures 4 cm.
Solution:
Given, side length of a pentagon = 4 cm = a
As we know, a regular pentagon has 5 sides, in which all the sides have equal measurements.
Hence, the perimeter of the regular pentagon = 5a = 5 (4) = 20 cm.
It can also be calculated as follows:
Perimeter of regular pentagon = 4 + 4 + 4 + 4 + 4 = 20 cm.
7. Determine the perimeter of a parallelogram, whose adjacent sides are 4 cm and 7 cm.
Solution:
Let a and b be the adjacent sides of a parallelogram.
Thus, a = 4 cm and b = 7 cm.
We know that the perimeter of a parallelogram = 2(a+b) units.
Now, substituting the values in the formula, we get
P = 2(4 + 7) cm
P = 2 (11) cm
P = 22 cm
Thus, the perimeter of the parallelogram = 22 cm.
Also, check: Perimeter of a Parallelogram.
8. Find the diameter of a circular sheet, if its perimeter is 154 cm. (Take π = 22/7)
Solution:
Given, Perimeter = 154 cm.
We know that, circumference or the perimeter of a circle = 2πr units
154 = 2 × (22/7) × r
154 × 7 = 44 × r
1078 = 44r
r = 1078/44
r = 24.5 cm
Hence, diameter = 2 × 24.5 = 49 cm
Therefore, the diameter of the circular sheet is 49 cm.
9. Calculate the perimeter of a quadrilateral whose side measures are given as 4 cm, 6 cm, 7 cm and 8 cm.
Solution:
As we know, a quadrilateral has 4 sides.
In general, the perimeter of a quadrilateral is equal to the sum of the four sides of a quadrilateral.
Thus, perimeter of the quadrilateral = (4 + 6 + 7 + 8) cm
P = 25 cm
Therefore, the perimeter of the quadrilateral is 25 cm.
10. Find the perimeter of a regular hexagonal, whose side length is 7.2 cm.
Solution:
Given: Side length of a regular hexagon, a = 7.2 cm.
As the hexagon has 6 sides, the perimeter of a regular hexagon = 6a units.
Now, substitute a = 7.2 cm in the formula, we get
Perimeter = 6 (7.2) = 43.2 cm
Thus, the perimeter of the regular hexagon is 43.2 cm.
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Watch The below Video to Understand the Perimeter of Shapes
Practice Questions
- Find the perimeter of a square whose side length is 8 cm.
- What is the perimeter of a circle, if the diameter is 18 m?
- Find the perimeter of an equilateral triangle, if the side length measures 5 inches.
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