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# Complement of a Set

Before studying about the Complement of a set, let us understand what are sets?

## Sets Definition

A well-defined collection of objects or elements is known as a set. Any set consisting of all the objects or elements related to a particular context is defined as a universal set. It is represented by

$$\begin{array}{l}U\end{array}$$
.
For any set A which is a subset of the universal set
$$\begin{array}{l}U\end{array}$$
, the complement of the set
$$\begin{array}{l}A\end{array}$$
consists of those elements which are the members or elements of the universal set
$$\begin{array}{l}U\end{array}$$
but not of the set
$$\begin{array}{l}A\end{array}$$
. The complement of any set
$$\begin{array}{l}A\end{array}$$
is denoted by
$$\begin{array}{l}A'\end{array}$$
.

## Complement of a Set Definition

If

$$\begin{array}{l}U\end{array}$$
is a universal set and
$$\begin{array}{l}A\end{array}$$
be any subset of
$$\begin{array}{l}U\end{array}$$
then the complement of
$$\begin{array}{l}A\end{array}$$
is the set of all members of the universal set
$$\begin{array}{l}U\end{array}$$
which are not the elements of
$$\begin{array}{l} A\end{array}$$
.

$$\begin{array}{l}A'\end{array}$$
= {
$$\begin{array}{l}{x ~:~ x~ ∈ ~U ~and ~x ~∉ ~A}\end{array}$$
}

Alternatively it can be said that the difference of the universal set

$$\begin{array}{l}U\end{array}$$
and the subset
$$\begin{array}{l}A\end{array}$$
gives us the complement of set
$$\begin{array}{l}A\end{array}$$
.

## Venn Diagram for the Complement of a set

The Venn diagram to represent the complement of a set A is given by: ### Complement of a Set Examples

To make it more clear consider a universal set

$$\begin{array}{l}U\end{array}$$
of all natural numbers less than or equal to 20.

Let the set

$$\begin{array}{l}A\end{array}$$
which is a subset of
$$\begin{array}{l}U\end{array}$$
be defined as the set which consists of all the prime numbers.

Thus we can see that

$$\begin{array}{l}A\end{array}$$
= {
$$\begin{array}{l}{2, 3, 5, 7, 11, 13, 17, 19}\end{array}$$
}

Now the complement of this set A consists of all those elements which is present in the universal set but not in

$$\begin{array}{l}A\end{array}$$
. Therefore,
$$\begin{array}{l}A'\end{array}$$
is given by:

$$\begin{array}{l}A'\end{array}$$
={
$$\begin{array}{l}{1,4,6,8,9,10,12,14,15,16,18,20}\end{array}$$
}

Example: Let

$$\begin{array}{l}U\end{array}$$
be the universal set which consists of all the integers greater than 5 but less than or equal to 25. Let
$$\begin{array}{l}A\end{array}$$
and
$$\begin{array}{l}B\end{array}$$
be the subsets of
$$\begin{array}{l}U\end{array}$$
defined as:

$$\begin{array}{l}A\end{array}$$
= {
$$\begin{array}{l}{x~:x~ ∈~U ~and~ x~ is~ a~ perfect~ square}\end{array}$$
}

$$\begin{array}{l}B\end{array}$$
=
$$\begin{array}{l}{7, 9, 16, 18, 24}\end{array}$$

Find the complement of sets A and B and the intersection of both the complemented sets.

Solution: The universal set is defined as:

$$\begin{array}{l}U\end{array}$$
= {
$$\begin{array}{l}{6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25}\end{array}$$
}

Also,

$$\begin{array}{l}A\end{array}$$
= {
$$\begin{array}{l}{9,16,25}\end{array}$$
} and

$$\begin{array}{l}B\end{array}$$
= {
$$\begin{array}{l}{7,9,16,18,24}\end{array}$$
}

The complement of set A is defined as:

$$\begin{array}{l}A'\end{array}$$
= {
$$\begin{array}{l}{x~:~x~∈~U~ and ~x~∉~A}\end{array}$$
}

Therefore,

$$\begin{array}{l}A'\end{array}$$
= {
$$\begin{array}{l}{6,7,8,10,11,12,13,14,15,17,18,19,20,21,22,23,24}\end{array}$$
}

Similarly the complement of set B can be given by:

$$\begin{array}{l}B'\end{array}$$
= {
$$\begin{array}{l}{6,8,10,11,12,13,14,15,17,19,20,21,22,23,25}\end{array}$$
}

The intersection of both the complemented sets is given by

$$\begin{array}{l}A’∩ B'\end{array}$$
.

Rightarrow A’∩ B’= {6, 8, 10, 11, 12, 13, 14, 15, 17, 19, 20, 21, 22, 23}

We can see from the above discussions that if a set

$$\begin{array}{l}A\end{array}$$
is a subset of the universal set
$$\begin{array}{l}U\end{array}$$
then the complement of set
$$\begin{array}{l}A\end{array}$$
i.e.
$$\begin{array}{l}A'\end{array}$$
is also a subset of
$$\begin{array}{l}U\end{array}$$
.

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