The equations that involve the trigonometric functions of a variable are called trigonometric equations. In the upcoming discussion, we will try to find the solutions of such trigonometric equations. We know that sin x and cos x repeat themselves after an interval of 2π and tan x repeats itself after an interval of π. The solutions of trigonometric equations which lie in the interval of [0, 2π] are called principal solutions. A trigonometric equation will also have a general solution expressing all the values which would satisfy the given trigonometric equation and it is expressed in a generalized form in terms of ‘n’.
Let us begin with a basic equation, sin x = 0.The principal solution for this case will be x = 0,π,2π as these values satisfy the given equation lying in the interval [0, 2π] . But, we know that if sin x = 0, then x = 0, π, 2π, π, -2π, -6π, etc. are solutions of the given equation. Hence general solution for sin x = 0 will be, x = nπ, where n∈I.
Similarly, general solution for cos x = 0 will be x = (2n+1)π/2, n∈I, as cos x has a value equal to 0 at π/2, 3π/2, 5π/2, -7π/2, -11π/2 etc.
Now, let us consider the equation, sin x = sin y. Let us try to find the general solution for this trigonometric equation.
sin x = sin y
⇒ sin x – sin y = 0
⇒2cos (x + y)/2 sin (x – y)/2 = 0
⇒cos (x + y)/2 = 0 or sin (x – y)/2 = 0
Upon taking the common solution from both the conditions, we get:
x = nπ + (-1)ny, where n∈I
Similarly, the general solution of cos x = cos y will be:
cos x – cos y = 0
2sin (x + y)/2 sin (y – x)/2 = 0
sin (x + y)/2 = 0 or sin (x – y)/2 = 0
(x + y)/2 = nπ or (x – y)/2 = nπ
On taking the common solution from both the conditions, we get:
x = 2nπ± y, where n∈I
Similarly to find the solution of equations involving tan x or other functions, we can use conversion of trigonometric equations. In other words, if tan x = tan y then;
Let us go through an example to have a better insight about solutions of trigonometric equations.
Example: sin 2x – sin 4x + sin 6x = 0
Solution:Given: sin 2x – sin 4x + sin 6x = 0
⇒sin 2x – sin 4x + sin 6x = 0
⇒2sin 4x.cos 2x – sin 4x = 0
⇒sin 4x (2cos 2x – 1) = 0
⇒sin 4x = 0 or cos 2x = ½
⇒4x = nπ or 2x = 2nπ ± π/3
Therefore the general solution for the given trigonometric equation is:
⇒x = nπ/4 or nπ ± π/6
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