## Relative Velocity:

We encounter occasions where one or more objects move in a frame which is non-stationary with respect to another observer. For example, a boat crosses a river that is flowing at some rate or an airplane encountering wind during its motion. In all such instances, in order to describe the complete motion of the object, we need to consider the effect that the medium is causing on the object. While doing so, we calculate the relative velocity of the object considering the velocity of the particle as well as the velocity of the medium. Here, we will learn how to calculate the** relative velocity**.

Let us consider two objects, A and B moving with velocities V_{a} and V_{b} with respect to a common stationary frame of reference, say the ground, a bridge or a fixed platform.

The velocity of the object A relative to the object B can be given as,

\(V_{ab}=V_{a}-V_{b}\)

Similarly, the velocity of the object B relative to that of object a is given by,

\(V_{ba}=V_{b}-V_{a}\)

From the above two expressions, we can see that

\(V_{ab}=-V_{ba}\)

Although the magnitude of the both the relative velocities is equal to each other. Mathematically,

\(\left |V_{ab} \right |=\left |V_{ba} \right |\)

**Examples of relative Velocity:**

We can understand the concept of relative velocity more clearly with the help of the following example.

** Example**: A plane is traveling atÂ velocity 100 km/hr, in the southward direction. It encounters wind traveling in the west direction at a rate of 25 km/hr. Calculate the resultant velocity of the plane.

Given, the velocity of the wind = V_{w} = 25km/hr

The velocity of the plane = V_{a}= 100 km/hr

The relative velocity of the plane with respect to the ground can be given as

The angle between the velocity of the wind and that of the plane is 90Â°. Using the Pythagorean theorem, the resultant velocity can be calculated as,

R^{2}= (100 km/hr)^{2}Â + (25 km/hr)^{2}

R^{2}= 10 000 km^{2}/hr^{2}Â + 625 km^{2}/hr^{2}

R^{2}= 10 625 km^{2}/hr^{2}

Hence,Â **R = 103.077 km/hr**

**Using trigonometry, the angle made by the resultant velocity with respect to the horizontal plane can be given as,**

\(tan\Theta =(\frac{window \: velocity}{aiprplane\: velocity})\\ \\ tan\Theta =(\frac{25}{100})\\ \\ \Theta =tan^{-1}\frac{1}{4}\\ \\ \Theta =14.0^{\circ}\)

Stay tuned with Byju’s to learn more about the concept of relative velocity, relative motion and other related topics.